作业帮(2)化简分式(1-x) (x-2) 2-1 (2-x),结果可能为 0吗?
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/07 15:40:37
（1）1/x-1/(x+1)=（x+1-x）/（x（x+1））=1/(x(x+1))(2)1/x(x+1)+1/(X+1)(x+2)+...+1/（x+999)(x+1000)=1/x-1/(x+1）
2/(x-1)÷(2/(x^2-1)+1/(x+1))=2/(x-1)÷(2/(x+1)(x-1)+1/(x+1))=2/(x-1)÷(2+x-1)/(x+1)(x-1)=2/(x-1)÷(x+1)/
就是分子分母同除以x所以x≠0
[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]/(x-4)/(x^3-2x^2)=(x+2)x^2(x-2)/[x(x-2)(x-4)]-(x-1)x^2(x-2)/[(x-2)^
原式=x+[1/(x-1)]-[(x-4)(x-1)/(x-1)(x+1)]=x+[1/(x-1)]-[(x-4)/(x+1)]……(x≠1)=x+1/(x-1)-{[(x+1)-5]/(x+1)}=
(1-x)/(x^2-1)=(1-x)/(x-1)(x+1)=-(x-1)/(x-1)(x+1)=-1/(x+1)祝你好运,学习进步
原式=[x^2+x-x/x^2-1]*(x-1)^2/x(x-1)=x^2/x^2-1*(x-1)/x=x/(x+1)令x=1则得到1/2很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满
原式=|x-1|/(x+3)(x-1）当x>1地时候~原式=1/(x+3)当x
分子为X^2(1+X)分母为(X+1)(X-1)上下约分,原式化为分子为X^2分母为X-1再问：分母是怎么化的再答：额，上面的算错了，分母我也化不出来，你确定题目是这样的？？再问：好像是的再答：是人教
2x/(x+2)-1=(2x-x-2)/(x+2)=(x-2)/(x+2)再问：第二部怎么来的再答：1=(x+2)/(x+2)2x/(x+2)-(x+2)/(x+2)通分=[2x-(x+2)]/(x+
原式=1(x+1)(x+2)+1(x+2)(x+3)+1(x+3)(x+4)=（1x+1-1x+2）+（1x+2-1x+3）+（1x+3-1x+4）=1x+1-1x+4=3x2+5x+4．
(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)=(x+1)(x-1)/(x+1)^2-(x+1)/(x-1)=(x-1)/(x+1)-(x+1)/(x-1)=[(x-1)^2-(x
@“理科家教”为你答疑（x²-1）分之（x²+x）=[（x+1）（x-1）]分之[x(x+1)]=（x-1）分之x@若不清楚欢迎追问,懂了请及时采纳!祝你学习进步!
原式=(x−1)(x+1)(x+1)2−x+1x−1=x−1x+1−x+1x−1=(x−1)2−(x+1)2(x−1)(x+1)=−4xx2−1；把x=0代入，得：原式=0；或把x=2代入，得：原式=
1.A.(X^2)/X=X或-XB.(X-2)/(X+1),是最简分式C.X/(X-1)是最简分式D.(2X+2)/(4X)=(X+1)/(2X)你是不是写错了?B和C都是最简分式2.A.(M^2-N
(x^2-1)/(x^2-2x+1)=[(x+1)(x-1)]/(x-1)^2=(x+1)/(x-1)
1)两边同时乘以x-2得：1-x+2(x-2)=-11-x+2x-4=-1x-3=-1x=2这是增根因此原方程无解2）原式=(1-x)/(x-2)+2+1/(x-2)=(1-x+2x-4+1)/(x-