(2x三次方)成(-2xy)除以2x的平方
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A-B=x³+2y³-xy²-(-y³+x³+2xy²)=x³+2y³-xy²+y³-x³
原式=2xy(4x²-2x-1)再问:求过程再答:没有提取公因式
原式化简:(2x^3-3x^2y-2xy^2)-(x^3-2xy^2+y^3)+(-x^3+3x^2y-y^3)=2x^3-3x^2y-2xy^2-x^3+2xy^2-y^3-x^3+3x^2y-y^
x³y³—2x²y²+xy=xy(x²y²-2xy+1)=xy[(xy)²-2xy+1]=xy(xy-1)²
原式=(x^4+xy³)-(2y^4+2x³y)=x(x³+y³)-2y(x³+y³)=(x-2y)(x³+y³)=(x
xy的三次方-2x²y²+x的三次方y=xy(y²-2xy+x²)=xy(x-y)²
1.x³-2x²y+xy²=x(x²-2xy+y²)=x(x-y)²2.8a²b-2b=2b(4a²-1)=2b(2a-
-xy(x²y的五次方-xy的三次方-y)=-x³y的6次方+x²y的4次方+xy²=-(xy²)³+(xy²)²+xy
上式化简的最终结果是-2y的平方,也就是与x无关,所以无论x取几,答案都一样为2
x²y³-2x(4xy³)=x²y³-2x²y³=-x²y³
x²y-2xy²+x³=x(xy-2y²+x²)=x(x+2y)(x-y)
(4x的三次方y+6x的二次方y的二次方-xy的三次方)÷2xy=xy(4x²+6xy-y²)÷2xy=2x²+3xy-0.5y²
原式=x^3+2x^2y+xy^2 =x(x^2+2xy+y^2) =x(x+y)^2再问:x-2��֮x-
-x三次方y-2x平方y平方-xy三次方=-xy(x²+2xy+y²)=-xy(x+y)²
x³y-2x²y+xy=xy(x²-2x+1)=xy(x-y)²
(x二次方-2x+1)二次方除(x-1)三次方=(x-1)四次方/(x-1)3次方=x-1=2010
原式=-x³y^6+x²y^4+xy²=-(xy²)³+(xy²)²+(xy²)=-2³+2²+2=
这是两题还是一题?再问:两题再答:那就好第一题:-2x²y-x³-xy²原式=-x(2xy+x²+y²)=-x(x+y)²第二题:a
原式=(-4)*(-2)*(x*x²)y³=8x³y³
m=x^2-3xy^2+2xy^2+3y^3,n=x^3-2x^2+xy^2-5y^3,则2x-7x^2*y^3+5xy^+14y^3等于多少?3m=3x^2-9xy^2+6xy^2+9y^3n=x^