(a a 2 2 a-2)÷1 a²-4选取一个合适的a值-搜答案-智慧作业帮

这是求值,不是因式分a(a-1)(a-2)(a-3)(a-4)=a(a-1)(a-4)(a-2)(a-3)=a(a^2-5a+4)(a^2-5a+6)=a[(a^2-5a)^2+10(a^2-5a)+

2013-03-1211:49提问者采纳原式=(a²+4a+4-a²-8)/(a²+4a+4)×(a²+2a)/(4a-4)=(4a-4)/(a+2)²

a/a-1÷（a-a/2a-1)

1、a/a-1÷（a-a/2a-1)=a/a-1/(a-a/2a-1)=1-1/(a-1/2-1)=1-1/(a-3/2)=1-2/(2a-3)=(2a-3-2)/(2a-3)=(2a-5)/(2a-

运用法则化简,把值带进去就行了

计算[jìsuàn]基本翻译computecalculate他们都含“计算”的意思.calculate指“通过计算或运算以解决疑难的题目或问题”,如:calculatethevelocityoflig

化简：原式=a/(a+1)-(a+3)/（a-1）*（a-1)^2/[(a+2)^2-1]=a/(a+1)-[（a-1)*(a+3)]/[(a+2-1)*(a+2+1)]=a/(a+1)-(a-1)/

1再问：过程？？？？？？？再答：可不好写…………再问：说说思路再答：a2+4a+4=(a+2)2a2+2a=a(a+2)通分，然后得到[a-4/a(a+2)2]/a-4/a+2然后约分，得到：1/a(

(a²+7a+10/a²-a+1)*(a3+1/a²+4a+4)÷(a+1/a+2)=[(a+2)(a+5)/(a²-a+1)]*[(a+1)(a²-

原式=[(a-2)/a(a+2)-(a-1)/(a+2)²]×(a+2)/(a-4)=(a²-4-a²+a)/a(a+2)²×(a+2)/(a-4)=(a-4)

{[(a-2)/a(a+2)]-[(2a-1)/(a-2)(a+2)]}÷(a+2)(a-1)/(a+2)^2先分解因式,再约掉（a+2）这个公因式=[(a-2）/a-（2a-1）/（a-2)]÷(a

[（a^2-5a+2)/(a+2)+1]÷(a^2-4)/(a^2+4a+4)=(a^2-4a+4)/(a+2)÷(a-2)(a+2)/(a+2)^2=(a-2)^2/(a+2)÷(a-2)/(a+2

{a×【a加5】}分之2再问：能否写下过程?谢谢了

(a+2/a²-2a-a-1/a²-4a+4)÷a-4/a=[(a+2)/a(a-2)-(a-1)/(a-2)²]×a/(a-4)=(a-4)/a(a-2)²×

(a-1)/(a+2)*(a²-4)/(a²-2a+1)÷1/(a²-1)=(a-1)/(a+2)*(a-2)(a+2)/(a-1)^2÷1/(a²-1)=(a

【（A+2）/（A²-2A）-（A-1）/（A²-4A+4）】×（A-2）/A÷（4-A）/A²=【（A+2）/A（A-2）-（A-1）/（A-2）²】×（A-

{1+4/a²-4}÷a/a-2

{1+4/a²-4}÷a/a-2=(a²-4+4)/(a²-4)÷a/(a-2)=a²/(a-2)(a+2)×(a-2)/a=a/(a+2)

[(a^2-4)/(a^2-4a+4)+1/(2-a)]÷2/(a^2-2a)=[(a+2)(a-2)/(a-2)^2-1/(a-2)]乘a(a-2)/2=[(a+2)/(a-2)-1/(a-2)]乘

再问：第二步我算的是a（a+2）（a+5）分之2a-8呢....好吧我去重算....

第一问,A=2　　第二问,A=±1.如果是小学,A=1　　第三问,A=0　　第四问,A=0