(x加y)的平方减y(2x加y)的差除(负2x)
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1/2再答:再问:谢谢了,问题解决了
x的平方-4x+y的平方+2y+5=x的平方-4x+4+y的平方+2y+1=(x-2)^2+(y+1)^2=0x-2=0x=2y+1=0y=-1x+y=2-1=1
x^2+2x+y^2-6y+10=0=(x^2+2x+1)+(y^2-6y+9)=0=(x+1)^2+(y^2-6y+3^2)=0=(x+1)^2+(y-3)^2=0x=-1y=3xy=-3
该试可以这样写:(x-1)的平方加(y+2)的平方等于0.所以X等于1,Y等于-2.那2X加Y等于0了.
x^2-2x+y^2+6y+10=0x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0x-1=0,y+3=0x=1,y=-3(x-y)/(x+y)=4/(-2)=-2
前者分子:x^2-y^2=(x+y)(x-y)那前面这项就可以化简约分啦后者分子:4x^2-4xy+y^2=(2x)^2-2*2xy+y^2=(2x-y)^2建议你理解一下x^2-2xy+y^=(x-
0<y<x【(x^2+y^2)(x-y)】-【(x^2-y^2)(x+y)】=【(x^2+y^2)(x-y)】-【(x-y)(x+y)^2】=(x-y)【(x^2+y^2-(x+y)^2】=(x-y)
x^2+2xy+y^2=25===>(x+y)^2=5^2===>x+y=±5(x-y)^2-3x+3y+2=0===>(x-y)^2-3(x-y)+2=0===>[(x-y)-1]*[(x-y)-2
/>∵x²+y²+6x+8y+25=0即(x+3)²+(y+4)²=0∴x=-3,y=-4∴x^y=3^-4=1/81再问:我一今做出来了,不过,谢谢
求根法:x^2+xy-2y^2+2x+7y-3=x^2+x(y+2)-2y^2+7y-3,△(x)=(y+2)^2-4(-2y^2+7y-3)=9y^2-24y+16=(3y-4)^2,x1=[-(y
x的平方减6xy加9y的平方减2x加6y加1=(x-3y-1)^2
x^2-4xy+4y^2-3x+6y+2=(x-2y)^2-3(x-2y)+2=(x-2y-1)(x-2y-2)
x^2+4x+y^2-2y+5=0(x^2+4x+4)+(y^2-2y+1)=0(x+2)^2+(y-1)^2=0x=-2,y=1x^2+y^2=(-2)^2+1^2=4+1=5
x^2-2x+y^2+8y+17=0(x-1)^2+(y+4)^2=0x=1;y=-4;
3∵x/y=1/2∴y=2x故(x^2+2xy+y^2)/(x^2-xy+y^2)=(x+y)^2/(x^2-xy+y^2)=(x+2x)^2/(x^2-x·2x+4x^2)=9x^2/(3x^2)=
解题思路:把分式的分子分母分解因式再根据法则进行计算,能约分的要先约分解题过程:答案见附件
x+y=2x^2-y^2+4y=(x+y)(x-y)+4y=2x-2y+4y=2x+2y=2(x+y)=4
y=3x^2-x+2--->3x^2-x+(2-y)=0判别式不小于0,故(-1)^2-4×3×(2-y)>=0--->-23+12y>=0--->y>=23/12故函数y的值域为[23/12,+无穷