从键盘输入n,输出小于n的所有完数

#include#includeintIsPrime(intx){inti;for(i=2;i

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

#includevoidmain(){\x09intn,i,j,t,a[10000];\x09printf("请输入正整数N:");\x09scanf("%d",&n);\x09printf("请依次

#include#includeusingnamespacestd;intmain(intargc,char*argv[]){inti;couti;cout

#includeintmain(){intn,num,max,min;scanf("%d",&n);for(inti=n;i>0;i--){scanf("%d",&num);if(i==n)//初始化

#includevoidperm(int*data,intn,intcurr){if(curr==n-1){for(inti=0;iprintf("%d",data[i]);printf("\n");

主函数这样intmain(){intsum=0;inti;intn;printf("Pleaseinputanumber:");scanf("%d",&n);for(i=1;i

#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a

#include#includeusingnamespacestd;intmain(){intm,k,n;cin>>m;n=0;for(k=sqrt(2*m)+1;k>1;k--)if((m*2-k*

#includemain(){intn,i,j,k=0,sum=0,a[100];printf("请输入一个数字\n");scanf("%d",&n);for(i=1;i

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

我只会PASCALvarn,i,max,min,j:longint;beginreadln(n);max:=-maxlongint;min:=maxlongint;fori:=1tondobeginr

//Note:YourchoiceisC++IDE#includeusingnamespacestd;longintSfun(constintN){longintsum=1;if(N==0||N==1

题目与程序的思路有一点点的偏差而已.程序是：n+(n-1)+(n-2)+(n-3)+...+2+1

不建议你用这种for(i=2;i=3){for(i=2;i

vara:array[1..100000]ofboolean;n,i:longint;beginfillchar(a,sizeof(a),false);a[2]:=true;readln(n);for

讲一下思路：判断一个数是否是质数的函数学过吧然后下面就是一个循环比如：for（intn=N；i>=2；i--){if(prime(n)){cout

#includevoidmain(){inti,j,n;printf("请输入n的值：\n");scanf_s("%d",&n);for(i=1;i

#includeintmain(){inti,j,n,k=0;scanf("%d",&n);for(i=2;i

voidfun(){intn,i,sum=0;printf("n=");scanf("%d",&n);for(i=n;i>=0;i--){if(i%5==0&&i%9==0)sum+=i;}print