从键盘输入一个数字 将数字的各个位相加

可参考如下scanf("%d",&num);printf("%d\n",num/100);printf("%d\n",num%10);---------------------------------

chara[100];gets(a);puts(a);inti;for(i=0;i

#include "stdio.h"void main(){  int n,sum=0;  printf(&q

#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a

#include"stdio.h"#include"math.h"intmain(void){charinput[100];printf("Pleaseinputthearray(int):");ge

#includeintmain(){intnum;inta,b,c;scanf("%d",&num);a=num/100;b=(num%100)/10;c=num%10;printf("a=%d,b=

#includeintmain(void){intnum,hundred,ten,indiv;printf("请输入一个三位整数:");scanf("%d",&num);hundred=num/100

假设你输入的数为x;unsignedchars[4];s[0]=x/1000;//四位数的千位s[1]=x/100%10;四位数的百位s[2]=x/10%10;四位数的十位s[3]=x%10;四位数的

staticvoidMain(string[]args){inta=int.Parse(Console.ReadLine());intb=a%10;intc=(a/10)%10;intd=(a/100

fpc:varn:string;a,b,i:longint;beginread(n);b:=0;a:=length(n);fori:=1toadob:=ord(n[i])-ord('0')+b;wri

importjava.io.BufferedReader;importjava.io.IOException;importjava.io.InputStreamReader;publicclassAd

#include"stdio.h"voidmain(){inti=10,k=0,sum=0,a;scanf("%d",&a);//输入一个数if(a=10);//当条件成立循环上面的语句sum+=a;

910.901...820.811.802.730...721...712...703.640.631.622.613.604.你会查吧640就是了

#includevoidmain(){intm,e,b,c,d,i,j,temp;scanf("%d",&m);e=m/1000;b=(m/100)%10;c=(m/10)%10;d=m%

ntmain(intargc,char*argv[]){charsound[10][5]={"yi","er","san","si","wu","liu","qi","ba","jiu","shi"}

#includevoidmain(){intnum;printf("输入一个3位数:\n");scanf("%d",&num);printf("个位:%d\n十位:%d\n百位:%d\n",num%1

cleaaccept"输入字符串："toChNL=len(Ch)Cnh=""fori=1toNLCa=substr(Ch,i,1)ifasc(ca)>=48andasc(ca)

importjava.util.Scanner;publicclassTest01{publicstaticvoidmain(String[]args){Scannerscan=newScanner(

#include"stdio.h"voidmain(){charch;scanf("%c",&ch);if(ch>='0'&&ch='a'&&ch='A'&&ch

intb[4];intsum=0;b[0]=a/1000;//千位b[1]=a%10;//个位b[2]=(a-b[1])%100;//十位b[3]=(a-b[0]*1000)/100;//百位for(