从键盘输入两个整数m和n,编程计算并输出最大值.输入mn 输出mn的最大值,

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

#includemain(){intm,n,k,j,s,t;printf("pleaseinputthenumberofm,n,k\n");scanf("%d",&m);scanf("%d",&n);

#includeusingnamespacestd;intmain(){inti,n,s=0;coutn;s=0;for(i=1;i

主函数这样intmain(){intsum=0;inti;intn;printf("Pleaseinputanumber:");scanf("%d",&n);for(i=1;i

#includevoidmain(){\x09intnum[100];\x09inti;\x09for(i=0;i

#includevoidmain(){intm,n,r,x;scanf("%d,%d",&m,&n);x=m*n;while(n!=0){r=m%n;m=n;n=r;}printf("%d%d\n",

#include "stdio.h"int main(){   int count1=0,count2=0,i;&nbs

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09a=a+b;\x09b=a-b;\x09a=a-b;\x09printf("%d%d"

//m与n的值不能太大,且用空格分隔.如：53#includeintfun(intn){\x09if(n==0||n==1)return1;\x09elsereturnn*fun(n-1);}void

不懂

#includeintmain(){intm,n;intsum1=0,sum2=0;scanf("%d%d",&m,&n);for(inti=m;i

#include#includeusingnamespacestd;boolprime(intn){\x09for(inti=2;in;\x09cout

#include#includevoidmain(){intn,s,j,i;printf("inputn(n

最大公约数:intGcd(inta,intb){if(a%b==0)returna;return(b,a%b);}最小公倍数:intGbs(inta,intb){returna*b/Gcd(a,b);

importjava.util.*;publicclassCombination{publicstaticvoidmain(String[]args){VectortestData=newVector

inta,b,max;scanf("%d",&a);scanf("%d",&b);max=Max(a,b);intMax(inta,intb){returna>b?a:b;}再问：确定吗这个答案？再答

clearinput"请输入第1个数："toainput"请输入第2个数："tobc=max(a,b)dowhile.t.ifc%a=0andc%b=0s=cexitendifc=c+1enddo"它

#includevoidprint(intspace,intnum,inttype){while(space--)putchar('');if(type){while(num--)putch

给你个可以加减乘除的!#includevoidmain(){floata,b;charc;printf("\n");scanf("%f%c%f",&a,&c,&b);if(c=='+')