先化简,再求值:a²-a分之6减a减1分之1
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 06:03:05
2a√(3ab³)-b/6*√(27a³b³)+2ab√(3ab/4)=2ab√(3ab)-a²b/2*√(3ab)+ab√(3ab)=3ab√(3ab)-a&
=[(a²-4)/(a-2)]×1/a(a+2)=[(a+2)(a-2)/(a-2)]×1/a(a+2)=(a+2)×1/a(a+2)=1/a
.(a-1分之3a剪a+1分之a)乘以a分之a²剪1=[3a/(a-1)-a/(a+1)]×(a+1)(a-1)/a=3a/(a-1)×(a+1)(a-1)/a-a/(a+1)×(a+1)(
1.(a-√3)(a+√3)-a(a-6)=a^2-3-a^2+6a=6a-3=6(√5+1/2)-3=6√5+3-3=6√52.x^2-5x=14(2x-1)(x-1)-(x+1)^2+1=2x^2
=(a-3)/2(a-2)÷[5/(a-2)-(a+2)(a-2)/(a-2)]=(a-3)/2(a-2)÷(5-a²+4)/(a-2)=(a-3)/2(a-2)×[-(a-2)/(a+3)
(a²+a)(a²-5a+6)分之(2a-a²)(a²+4a+3)=(2a-a²)(a²+4a+3)/(a²+a)(a²
∵|a+3b+1|≥0,(2a-4)2≥0,且|a+3b+1|+(2a-4)2=0,∴2a-4=0且a+3b+1=0,∴a=2,b=-1(3分),∵原式=3a2b-(2ab2-2ab+3a2b)+2a
a-a/3+1-a+a/2-3/a²-a²/4-6a+9=-35a/6-3/a²-a²/4+10a取6,得-35-1/12-9+10=-34又1/12
=(a²+ab-a²)/(a+b)×(a-a+b)/(a-b)×(a+b)/b²=ab/(a+b)×b/(a-b)×(a+b)/b²=a/(a-b)
(a+2a+1)/(a-1)-a/(a-1)=(a+1)^2/(a+1)(a-1)-a/(a-1)=(a+1)/(a-1)-a/(a-1)=1/(a-1)由a=根号3+1,所以原式=1/(a-1)=1
原式=(3+a)(3-a)/(a+3)^2x(a+3)/(a-3)a-1/a=-1/a-1/a=-2/a=-2/根号2=-根号2
答:a=1/(2+√3)=(2-√3)/[(2+√3)(2-√3)]=(2-√3)/(4-3)=2-√3所以:0
原式=12a2b-32a2b+6abc+2a2c-3abc=-a2b+2a2c+3abc,当a=-1,b=-3,c=12时,原式=3+1+4.5=8.5.
再答:你不要像我这样画掉我这样只是为了方便我计算
a/(a-3)-(a+6)/(a²-3a)+3/a=(a²-a-6+3a-9)/a(a-3)=(a²+2a-15)/a(a-3)=(a-3)(a+5)/a(a-3)=(a
原式=(a+2ab+b)-(a-2ab+b)=4ab,当a=3,b=4时,原式=4ab=412=83.
[(a-12)2-(a+12)2](a+3),=[(a-12)+(a+12)][(a-12)-(a+12)](a+3),=-2a(a+3),当a=-2时,原式=-2×(-2)×(-2+3)=4.
(a-2)分之a-(a²-2a)分之2a-a分之2=[a(a-2)]分之a²-[a(a-2)]分之(2a)-[a(a-2)]分之[2(a-2)]=[a(a-2)]分之[a²