先化简再求值x的平方减9除以x分之x-3-搜答案-智慧作业帮

【1-1/x-1】除以x的平方-4x+4/x的平方-1=（1-1/x-1）÷x-4x+4/x-1=-1/x÷x-4x+4/x-1=-1/x+4/x-1-4x=-1/3+4/3-1-4*3=-1/27+

{1-[(X-1)/(1-X)]^}/{(X^-X+1)/(X^3-2X+1)}={1+[(X-1)/(X-1)]^}/{(X^-X+1)/(X^3-2X+1)}=4/{(X^-X+1)/(X^3-2

x的平方-1/x的平方-2x+1除以x+2/x-1减去1/x+2=(x-1)(x+1)/(x-1)²÷(x+2)/(x-1)-1/(x+2)=(x+1)/(x-1)*(x-1)/(x+2)-

(x+1)分之1-(x²-6x+9)分之(3-x)÷(x-3)分之(x²+x)=(x+1)分之1-(x-3)²分之[-(x-3)]÷(x-3)分之[x(x+1)]=(x+

原式=(x+1)/x÷(2x²-1-x²)/2x=(x+1)/x÷(x²-1)/2x=(x+1)/x÷(x+1)(x-1)/2x=(x+1)/x*2x/(x+1)(x-1

原式=[X-X/(X-1)]/[1+1/(X²-1)]=[X(X-1)-X]/[X-1+1/(X+1)]分子分母都乘以(X-1)=(X²-2X)(X+1)/[X²-1+1

(x-1/x)/((x²-2x+1)/x)=((x²-1)/x)/((x-1)²/x)=(x+1)(x-1)/(x-1)²=(x+1)/(x-1)=6/4=3/

再问：(x加2）吗？再答：什么？再问：第一个括号里的是x加几

原式=(2-x-x-2)/(x+2)*(x+2)(x-2)/2x=-2x/(x+2)*(x+2)(x-2)/2x=-1/(x-2)=-1/(2-√2-2)=√2/2

你的式子太乱了,而且开头就是x=,分子分母分别用括号括起来,加减时也用括号括起来,一部分一部分的写清楚些再问：题目就是这样再答：那你看一下是不是我写的这个式子：x=((2-x-1)/2)/(x^2-(

1/x+1-3-x/x的平方-6x+9除以/x的平方+x/x-3=1/(x+1)+(x-3)/(x-3)²÷x(x+1)/(x-3)=1/(x+1)+1/x(x+1)=(x+1)/x(x+1

x的平方-6x+9除以2x的平方-18=(x-3)^2/2(x+3)(x-3)=(x-3)/2(x+3)=44/100=11/25

/>（2x-x分之1+x的平方）除以x分之x-1,其中x=根号2=[2x²-(1+x²)]/x÷(x-1)/x=(x²-1)/(x-1)=(x-1)(x+1)/(x-1)

原式=[(x-1+1)/(x-1)]*[(x^2-1)/x]=[x/(x-1)]*[(x+1)(x-1)/x]=x+1=-2+1=-1

原式=(3+x)(3-x)/(x+3)²×2(x+3)/x(x-3)-2/x(x-2)=-2/x-2/x(x-2)=[-2(x-2)-2]/x(x-2)=(2-2x)/x(x-2)当x=5时

分子分母同乘以4.再一化简

x²+x-2=0(x-1)(x+2)=0x=1或x=-2(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=(x²-x+1)/(x-1)*(1-x)