分式x y 通缩小
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2/xy=2(y-x)/xy(y-x)3y/(xy-x^2)=3y^2/xy(y-x)如果不懂,请追问,祝学习愉快!
x²+y²-2x-6y+10=0把10拆成“1+9”∴(x²-2x+1)+(y²-6y+9)=0∴(x-1)²+(y-3)²=0∴x-1=0
x-y=x/y两边同乘以y得xy-y^2=x移项xy-x=y^2即x(y-1)=y^2x=y^2/(y-1)
(x^2-xy)/(xy^2)·y/(y-x)=x(x-y)/(xy^2)·y/(y-x)=(x-y)/(y^2)·y/(y-x)=-1/y再答:二十年教学经验,专业值得信赖!如果你认可我的回答,敬请
x=-2y(2xy+y^2)/(x^2-xy)=(-4y^2+y^2)/(4y^2+2y^2)=-3y^2/(6y^2)=-1/2再问:我算出来也是-1/2,可答案说是-15/28
2(x+3)分之x和(x-3)分之y的乘积
不算,x有可能等于0
xy+x/x的平方+2x+1=x(y+1)/(x+1)^2不能继续约分了题目如果是xy+y/x的平方+2x+1=y(x+1)/(x+1)^2=y/(x+1)
xy/x+y=1/2xy=2(x+y)3x-xy+3y/x-xy+y=[3(x+y)-2(x+y)]/[(x+y)-2(x+y)]=(x+y)/[-(x+y)]=-1
原式=x(x+y)分之x(x-y)=(x+y)分之(x-y)
因为x+2y=0,所以x=-2y原式=(x^2+2xy)/(xy+y^2)=(4y^2-4Y^2)/(-3y^2+y^2)=0/(-2y^2)又因为xy不等于零,所以x、y君不等于零,所以-2y^2亦
x+2y=0,xy不等于0∴x=-2yx²+2xy/xy+y²=(4y²-4y²)/(-2y²+y²)=0
(xy-x²)·xy/x-y=x(y-x)·xy/x-y=-x²y
y-x=3xyx-y=-3xyx-2xy-y=-5xy2x+3xy-2y=2(x+y)+3xy=-6xy+3xy=-3xy分式x-2xy-y分之2x+3xy-2y=5/3
你是从长期来看这个问题,还是短期的.
原式=(x²-y²)/xy+y(x-y)/x(x-y)=(x²-y²)/xy+y/x=(x²-y²+y²)/xy=x²/
看不懂你的问题,不过只要分母中含字母的代数式就是分式,要看题目中的式子,不用化简后再看.
2xy/x+y2x.2y/2x+2y=4xy/2*(x+y)=2xy/x+y不知道对不对