分解因式x的平方减2xy加y的平方减5x加5y减5
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(x-y)(x-y-2)-3
答:-x³y+2x²y-xy=-xy(x²-2x+1)=-xy(x-1)²
xy^2-2xy+2y-4=xy(y-2)+2(y-2)=(xy+2)(y-2)
x³-2x²y+xy²=x(x²-2xy+y²)=x(x-y)²
3x³-6x²y+3xy²=3x(x²-2xy+y²)=3x(x-y)²
8(x^2-2y^2)-x(7x+y)+xy=8x^3-16y^2-7x^2-xy+xy=8x^3-16y^2-7x^2无法再分解
求根法:x^2+xy-2y^2+2x+7y-3=x^2+x(y+2)-2y^2+7y-3,△(x)=(y+2)^2-4(-2y^2+7y-3)=9y^2-24y+16=(3y-4)^2,x1=[-(y
(x+3)(x-1)
双十字相乘.
原式=2[x^2+1/2xy+(y/4)^2]-y^2-1/8*y^2=2(x+y/4)^2-9/8*y^2=[√2(x+y/4)+(√9/8)y]*[√2(x+y/4)-(√9/8)y]上式再化减一
由x³-2x²y+xy²-x=x(x²-2xy+y²-1)=x[(x-y)²-1]=x(x-y-1)(x-y+1).再问:分解因式:-49x
1x²+2xy-3y²=x²+2xy+y²-4y²=(x+y)²-(2y)²=(x+y+2y)(x+y-2y)=(x+3y)(x-
解(1/2)x²+2xy+2y²=(x²+4xy+4y²)/2=(x+2y)²/2
=(x²+4xy+4y²)/2=(x+2y)²/2
2x³-8x²y+8xy²=2x(x²-4xy+4y²)=2x(x-2y)²
原式=(x+y)(x+2y)+2(x+2y)=(x+2y)(x+y+2)希望我的回答能帮助到您,
2x^2-4xy+2y^2=2(x^2-2xy+y^2)=2(x-y)^2
(x-y+z)(x-y-z)
(1)3x²-4xy+6y²Δ=4²-4×3×6=16-72
(xy-1)^2+(x+y-2xy)(x+y-2)=(xy-1)^2+4xy+(x+y)^2-2(xy+1)(x+y)=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)=(x+1)^2(y+