化简(x x平方 x-1)除以x平方-1 x平方 2x 1-搜答案-智慧作业帮

原式=[x²－4xy＋﹙2y﹚²－1]／﹙x－2y－1﹚=[﹙x－2y﹚²－1²]／﹙x－2y－1﹚=﹙x－2y＋1﹚﹙x－2y－1﹚／﹙x－2y－1﹚=x－2

x+2分之x平方-2x-x-1分之x平方-4X+4除以x平方-16分之x平方+4x=x(x-2)/(x+2)÷(x-2)^2/(x-1)÷[x(x+4)/(x+4)(x-4)]=[x(x-2)/(x+

原式=[2(x-3)/(x-2)²]÷(x+3)×(x+3)(x-2)/[-(x-3)]=-2(x-3)(x+3)(x-2)/[(x-2)²(x+3)(x-3)]=-2/(x-2)

((x+2)/(x^2-2x)-(x-1)/(x^2-4x+4))/((x^2-16)/(x^2+4x))=((x+2)(x-2)-(x-1)x)/((x-2)^2*x)/((x-4)/x)=((x-

格式有点乱,〖((1-x)/(3-x))^2/((x^2-6x+9)/(9-x^2 ))〗^ ×1/(x^2-2x+1)=〖((1-x)/(3-x))^2/(〖(X-3)〗^2/(

4x三次除以(-2x)平方-(2x平方-x)除以(1/2x)=4x^3/4x^2-(2x^2-x)/(1/2x)=x-2x(2x-1)/x=x-2(2x-1)=x-4x+2=-3x+2

/>分式有意义,x-1≠0x≠1x+|(1+x²-2x)/(x-1)|=x+|(x-1)²/(x-1)|=x+|x-1|x>1时,原式=x+x-1=2x-1x

(2x-6)除以(X平方-4x+4)除以(x+3)乘以(x平方+x-6)除以(12-4x)=2(x-3)/(x-2)^2/(x+3)*(x+3)(x-2)/4(3-x)=-2(x-3)/[(x-2)^

1除以(x的平方+3x+2)+1除以(x平方+5x+6)+1除以(x平方+7x+12)=1/（x+1）（x+2）+1/(x+2)(x+3)+1/(x+3)(x+4)=1/(x+1)-1/(x+2)+1

题目是（5x+2)/(x²+x)=3/(x+1)这样吧?∵（x+1）作分母,不为0,可直接约分∴（5x+2)/x=3∴5x+2=3x∴2x=-2∴x=-1

原式=[(x-1+1)/(x-1)]*[(x^2-1)/x]=[x/(x-1)]*[(x+1)(x-1)/x]=x+1=-2+1=-1

(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]=x(x-3)/(x+3)x的平

将3x/(x-1)-x/(x+1)通分得

x²/(x-1)-x=(x²-x²+x)/(x-1)=x/(x-1)

(x^2-x-2)/(x+1)=(x-2)(x+1)/(x+1)=x-2

原式=x[2(x-2)-(x+2)]/(x+2)(x-2)*(x+2)(x-2)/x=2(x-2)-(x+2)=2x-4-x-2=x-6

x平方-x-2/x平方-x-6除以x平方+4x-5/x平方+3x-10=[(x-2)(x+1)/(x-3)(x+2)]/[(x+5)(x-1)/(x+5)(x-2)]=[(x-2)(x+1)/(x-3

x的平方-1分之x除以x的平方分之x的平方=x²-(x/1)/(x²/x²）=x²-(x)/1=x²-x