化简求值:a 1分之1-搜答案-智慧作业帮

=1/(a+2)+4/(a+2)(a-2)=(a-2+4)/(a+2)(a-2)=1/(a-2)=1/(2+√3-2）=√3/3

是(x^2/(x-1)-x+1)/(4x^2/(1-x)-4x+1)吗原式=(x-x+1)(x+x-1)/(x-1)/((4x^2-4x+1+4x^2-x)/(1-x))=-(2x-1)/(4x^2-

[1/(x-y)-1/(x+y)]÷2y/(x^2-2xy+y^2)=[(x+y)/(x+y)(x-y)-(x-y)/(x+y)(x-y)]÷2y/(x-y)^2=[(x+y-x+y)/(x+y)(x

（a²-4a+3）分之（a²-4）×（a²+3a+2）分之（a-3)-(a²-1）分之（a+3）=(a+2)(a-2)/(a-3)(a-1)x(a-3)/(a+

第一题原试=(4/(x-2)(x+2)-(x+2)/((x-2)(x+2)))*(x-2)=(2-x)/((x+2)(x-2))*(x-2)=(2-x)/(x+2)带入x=2013=-2011/201

(a+1分之1-a的平方-1分之a-2)除以a+1分之1=1/(a+1)x(a+1)-(a-2)/(a+1)(a-1)x(a+1)=1-(a-2)/(a+1)=(a+1-a+1)/(a+1)=2/(a

第一题化简成:m(m-2)分之(m-1)(m-2)...（m-2）消掉.最简(m-1)/m再问：麻烦详细点，谢谢！！！~~~再答：是那里没看懂？分母是把m提出来，分子是十字相乘法

(x-4)(2x-5)-(3x-2)(x+6)=(2x²-13x+20)-(3x²+16x-12)=2x²-13x+20-3x²-16x+12=-x²

由（-27/8)^(-2/3)+(0.002)^(-½)-10(√5-2)-¹+(√2-√3)=(-4/9)+10√5-10(√5+2)+√2-√3=-184/9+√2-√3

1/a+√(1/a²+a²-2)=1/a+√(1/a-a)²=1/a+|1/a-a|∵1/a=5>a∴原式=1/a+1/a-a=2/a-a=10-1/5=49/5∴甲的对

a=根号2-1∴a-1

原式=1/a+√(1/a²+a²-2)=1/a+√(1/a-a)²=1/a+1/a-a=2/a-a=10-1/5=9.8

解1/(a+1)-(a+1)/(a²-2a+1)÷(a+1)/(a-1)=1/(a+1)-(a+1)/(a-1)²×(a-1)/(a+1)=1/(a+1)-1/(a-1)=(a-1

结果-34,太简单了.

原式=（x-2+2x+4)/(x+2)(x-2）*x(x+2)/3x+2)=x/(x-2)当x-2+根号3时,原式=（2+根号3）/（2+根号3）-2=（2根号3+3）/3

{1-x/(x-1)}÷1/x(x-1)=(x-1-x)/(x-1)÷1/x(x-1)=-1/(x-1)÷1/x(x-1)=-x

化简求值(求值)

解题思路：解：x^2-3x+1=0x-3+(1/x)=0x+(1/x)=3所以x+=(x+1/x)-2=3-2=9-2=7因为网站有规定，每次只解一题，希望你在提问广场再提问一次好吗？解题过程

[（x+2)/x-(x-1)/(x-2)]÷（x-4)/x=[1+2/x-1-1/(x-2)]×x/(x-4)=(x-4)/x(x-2)×x/(x-4)=1/(x-2)=1/(3-2)=1这是我在静心

(x+1分之1+x-1分之1)·(x平方-1)=x+1分之1·(x平方-1)+x-1分之1·(x平方-1)=x-1+x+1=2x