2x [2分之1乘以x的平方-1]-3x
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(1-x)^2/(x^2+4x+4)/(x-1)^2*(x^2+3x+2)/(x-1)=(x+1)/(x+2)(x-1)=(x+1)/(x^2+x-2)再问:是1-x的平方,不是(1-x)的平方再答:
题目应是 已知y=x的平方-1分之x的平方-2x+1除以x+1分之x的平方-x乘以5x,试说明在代数式有意义的情况下,不论x取何值,y的值都不变y=(x^2-2x+1)/(x^2-1)÷(x^2-x)
(x分之x的平方-y的平方)乘以(x的平方-2xy+y的平方分之2x)其中x=2y=1=(x^2-y^2)/x*2x/(x-y)^2=(x+y)(x-y)/x*2x/(x-y)^2=2(x+y)/(x
首先计算(x+3)/(x^2-1)乘以(x^2-2x+1)/(x^2+4x+3),分解因式可以得到(x+3)/(x+1)(x-1)乘以(x-1)^2/(x+3)(x+1),约分后等于(x-1)/(x+
x减1分之x平方减1,化简为x+1得2005+1=2006第二问不太清楚
=(x+1)/x*(2x)^2/(x+1)^2-(2/x^2-1)=4x/(x+1)-2/(x^2-1)=(4x^2-4x-2)/(x^2-1)再问:*和^是什么意思?
原式=2(x+3)(x-2)/(x-2)²x(x+3)-1/(x-2)=2/x(x-2)-1/(x-2)=(2-x)/x(x-2)=-x
2X的平方+8X+8分之X的平方+2X+1除以(X+1)乘以X+1分之X+2=(x^2+2x+1)/(2x^2+8x+8)*1/(x+1)*(x+2)/(x+1)=(x+1)^2/2(x^2+4x+4
[(x^3-x)/(x^2-2x+1)]*(x-1)/x=[x(x^2-1)/(x-1)^2]*(x-1)/x=[x(x-1)(x+1)/(x-1)^2]*(x-1)/x=x+1=√2-1+1……(因
)【(x²-2x+1)/(x²-1)】÷【(x-1)/(x²+x)】=【(x-1)²/(x+1)(x-1)】÷【(x-1)/x(x+1)】=【(x-1)/(x+
∵x=-1/2∴2x=2×(-1/2)=-1
原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(
(2-X)的平方可以变成(X-2)的平方
(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)
3分之1乘以x的平方+2x+3=1/3(x^2+6x+9)=1/3(x+3)^2再问:还有几个您也帮我解了吧,不胜感激5x-30乘以x的平方+45乘以x的3次方12mn-m的平方乘以n-36n(x-2
(x+1)分之1-(x²-1)分之1×(x+1)分之(x²-2x+1)=(x+1)分之1-[(x+1)(x-1)]分之1×(x+1)分之(x-1)²=(x+1)分之1-(
原式=x²+x/2-2-x/2+2=x²
4b分之3a乘以9a的平方分之2b=3a/(4b)×2b/(3a)²=1/(6a)x的平方+2x+1分之x除以x的平方-1分之x的平方+2x=x/(x+1)²÷[x(x+2)/(x
“x的平方-4x+4分之x-1乘以2x-2分之x的平方-4”数学表示式是:[(x-1)/(x-4x+4)]×[(x²-4)/(2x-2)];原式=[(x-1)/(x-2)²]×{[