2x2-xy-6y2 2x 17y-12 因式分解

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当多项式x2+3kxy-2y2+6xy-1中不含xy项时,求k的值.

原式=x2+(3k+6)xy-2y2-1,因为不含xy项,故3k+6=0,解得:k=-2.

已知x2+y2-10x-6y+34=0,求(x-y/x+y)2÷x2-y2/xy×x2+2xy+y2/x2-xy 的值.

你好x²+y²-10x-6y+34=0(x-5)²+(y-3)²=0每项都大于等于0,只有等于0时上式才成立,所以x=5y=3(x-y/x+y)²÷(

(8xy-3x2)-5xy-3(xy-2x2+3)

A=-6-4+2+1=-7,B=6+4-2+1=9A-2B=-7-2x9=-25

因式分解 x2+xy-2y2-x+7y-6

x^2+xy-2y^2-x+7y-6=(x+2y)(x-y)-x+7y-6x+2y-3Xx-y2十字相乘得:2(x+2y)-3(x-y)=-x+7y是一次项所以原式=(x+2y-3)(x-y+2)

1,1,X2-1-2xy+y2

X2-1-2xy+y2=X2-2XY+Y2-1=(X2-2XY+Y2)-1=(X-Y)2-1=(X-Y-1)(X-Y+1)(x2+4y2)2-16x2y2=(x2+4y2)2-(4XY)2=(X2+4

若X2+Y2-2X-6Y+10=0 ,求(x2-y2)/xy的值

10拆成1+9X2-2X+1+Y2-6Y+9=0(X-1)2+(Y-3)2=0平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.所以两个都等于0所以X-1=0,Y-3=0X=1,Y=

已知X2-2x+y2+6y+10=0,求(x2-2xy)/(xy+y2)的值

x²-2x+y²+6y+10=0,变换得(x-1)²+(y+3)²=0,∴x=1,y=-3∴(x2-2xy)/(xy+y2)=(1²-2*(-3))/

2x2-xy+3y2因式分解

十字相乘法原式=(2x-3y)(x+y)

因式分解:x2-2xy+y2-z2.

原式=(x2-2xy+y2)-z2=(x-y)2-z2=(x-y+z)(x-y-z).

约分 xy+2y/x2次方-4

y(x+2)/(x-2)(x+2)=y/(x-2)提取yx²-4=(x-2)(x+2)

已知(3x-6)2+|2-2y|=0,求3xy+2(x2+2y)-3(xy+x2)的值.

原式=3xy+2x2+4y-3xy-3x2=(3xy-3xy)+(2x2-3x2)+4y=-x2+4y∵(3x-6)2+︳2-2y|=0∴x=2,y=1把x=2,y=1代入原式=-(-2)2+4×(-

已知6x2减去xy减去15y2等于0,求分式2x2减去3xy减去3y2分之x2减去2xy+4y2

6x2-xy-15y2=(2x+3y)(3x-5y)=0,所以x=-3/2y或x=5/3y

x2 y2+3xy+2 因式分解

x2y2+3xy+2=(xy)^2+3xy+2=(xy+2)(xy+1)很高兴能帮助您~!

(-2x2次方y)乘(-三分之二xy)乘(-8xy)

(-2x2次方y)乘(-三分之二xy)乘(-8xy)=-32/3X^(2+1+1)Y^(1+1+1)=-32/3*X^4Y^3

计算:12xy+(3x2-5xy)-2(3xy+2x2).

原式=12xy+3x2-5xy-6xy-4x2,=xy-x2.

已知2x2+xy=6,3y2+2xy=9,求4x2+8xy+9y2的值为______.

∵4x2+8xy+9y2=4x2+2xy+9y2+6xy=2(2x2+xy)+3(3y2+2xy),2x2+xy=6,3y2+2xy=9,∴2(2x2+xy)+3(3y2+2xy)=2×6+3×9=3

因式分解:(1)(a+b)2+6(a+b)+9;(2)-2xy-x2-y2(3)(x2-2xy)2+2y2(x2-2xy

(1)(a+b)2+6(a+b)+9,=(a+b+3)2;(2)-2xy-x2-y2,=-(x2+2xy+y2),=-(x+y)2;(3)(x2-2xy)2+2y2(x2-2xy)+y4,=(x2-2

分解因式:x2-2xy+y2-9

x2-2xy+y2-9,=x2-2xy+y2-9,=(x2-2xy+y2)-9,=(x-y)2-32,=(x-y+3)(x-y-3).

已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/x

因为x²+4y²+x²y²-6xy+1=0(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²