2x2-xy-6y2 2x 17y-12 因式分解
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原式=x2+(3k+6)xy-2y2-1,因为不含xy项,故3k+6=0,解得:k=-2.
你好x²+y²-10x-6y+34=0(x-5)²+(y-3)²=0每项都大于等于0,只有等于0时上式才成立,所以x=5y=3(x-y/x+y)²÷(
A=-6-4+2+1=-7,B=6+4-2+1=9A-2B=-7-2x9=-25
x^2+xy-2y^2-x+7y-6=(x+2y)(x-y)-x+7y-6x+2y-3Xx-y2十字相乘得:2(x+2y)-3(x-y)=-x+7y是一次项所以原式=(x+2y-3)(x-y+2)
(x+ay+ax^2+3x+2)(x+by+by^2+2y-3)
X2-1-2xy+y2=X2-2XY+Y2-1=(X2-2XY+Y2)-1=(X-Y)2-1=(X-Y-1)(X-Y+1)(x2+4y2)2-16x2y2=(x2+4y2)2-(4XY)2=(X2+4
10拆成1+9X2-2X+1+Y2-6Y+9=0(X-1)2+(Y-3)2=0平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.所以两个都等于0所以X-1=0,Y-3=0X=1,Y=
x²-2x+y²+6y+10=0,变换得(x-1)²+(y+3)²=0,∴x=1,y=-3∴(x2-2xy)/(xy+y2)=(1²-2*(-3))/
十字相乘法原式=(2x-3y)(x+y)
原式=(x2-2xy+y2)-z2=(x-y)2-z2=(x-y+z)(x-y-z).
y(x+2)/(x-2)(x+2)=y/(x-2)提取yx²-4=(x-2)(x+2)
原式=3xy+2x2+4y-3xy-3x2=(3xy-3xy)+(2x2-3x2)+4y=-x2+4y∵(3x-6)2+︳2-2y|=0∴x=2,y=1把x=2,y=1代入原式=-(-2)2+4×(-
6x2-xy-15y2=(2x+3y)(3x-5y)=0,所以x=-3/2y或x=5/3y
x2y2+3xy+2=(xy)^2+3xy+2=(xy+2)(xy+1)很高兴能帮助您~!
(-2x2次方y)乘(-三分之二xy)乘(-8xy)=-32/3X^(2+1+1)Y^(1+1+1)=-32/3*X^4Y^3
原式=12xy+3x2-5xy-6xy-4x2,=xy-x2.
∵4x2+8xy+9y2=4x2+2xy+9y2+6xy=2(2x2+xy)+3(3y2+2xy),2x2+xy=6,3y2+2xy=9,∴2(2x2+xy)+3(3y2+2xy)=2×6+3×9=3
(1)(a+b)2+6(a+b)+9,=(a+b+3)2;(2)-2xy-x2-y2,=-(x2+2xy+y2),=-(x+y)2;(3)(x2-2xy)2+2y2(x2-2xy)+y4,=(x2-2
x2-2xy+y2-9,=x2-2xy+y2-9,=(x2-2xy+y2)-9,=(x-y)2-32,=(x-y+3)(x-y-3).
因为x²+4y²+x²y²-6xy+1=0(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²