3x³-7x²-3x-9因式分解
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16(3x+1)=9(x+2)[4(3x+1)]-[3(x+2)]=0[(4(3x+1)+3(x+2)][4(3x+1)-3(x+2)]=0(15x+10)(9x-2)=0解得:15x+10=0或9x
解(x-3)²+2x(x-3)=0(x-3)(x-3+2x)=0(x-3)(3x-3)=0∴x=3或x=1再问:应该用提公因式法?再答:提了提了(x-3)∴(x-3)²+2x(x-
(3x-2)(5x+1)=0,✘1=-1/5,✘2=2/3再问:给个过程再答:这不是过程吗?再答:后面的提2出来,再答:在移项再问:咋变的再答:2(5x+1)再问:好了我会
(x-3)²=2x(3-x)(3-x)²=2x(3-x)(3-x-2x)(3-x)=0(3-3x)(3-x)=0x1=1,x2=3
(x+3)(x-1)=x+3(x+3)(x-1)-(x+3)=0(x+3)[(x-1)-1]=0(x+3)(x-2)=0x+3=0,x-2=0x1=-3,x2=2
x^2+5+7=3x+1x^2-3x+11=0(x-3/2)^2-9/4+11=0(x-3/2)^2+35/4=0(x-3/2)^2=-35/4因为(x-3/2)^2≥0所以无解
【参考答案】7x(3-x)=3(3-x)方程两边同时提取3-x得(3-x)(7x-3)=0即3-x=0,或7x-3=0解得x=3或3/7不理解欢迎追问
(2x-1)(x+1)=(3x+1)(x+1)(2x-1)(x+1)-(3x+1)(x+1)=0(x+1)(2x-1-3x-1)=0(-x-2)(x+1)=0-x-2=0x+1=0则x1=-2x2=-
7X(2X-3)=4(3-2X).7x(2x-3)+4(2x-3)=0(7x+4)(2x-3)=0x1=-4/7x2=3/2在右上角点击【评价】,然后就可以选择【满意,问题已经完美解决】了.如还有新的
原方程就是X^2-5x-3=0X^2-5x+25/4-37/4=0(x-5/2)^2-(√37/2)^2=0(x-5/2+√37/2)(x-5/2-√37/2)=0x=5/2-√37/2或者x=5/2
(2x-3)²-9(3-2x)-10=0(2x-3)²+9(2x-3)-10=0(2x-3-1)(2x-3+10)=0x=2或x=-7/2
6x²+7x-3=0(3x-1)(2x+3)=03x-1=02x+3=0x=1/3或x=-3/2
再答: 再答: 再答:
十字相乘x6x-3x²+3x-18=(x+6)(x-3)或拆项,将-3X拆成-6X+3X,再分组来x²-3x-18=x²-6x+3x-18=(x²-6x)+(3
(x-1)(2x+3)+x(1-x)=0(x-1)(2x+3)-x(x-1)=0(x-1)(2x+3-x)=0(x-1)(x+3)=0x-1=0x=1x+3=0x=-3
2(x-3)²=x²-92(x-3)²-(x²-9)=02(x-3)²-(x-3)(x+3)=0(x-3)(2x-6-x-3)=0(x-3)(x-9)
x(2x+3)=0相乘为0则两个因式哪个至少有一个是0所以x=0或2x+3=0所以x=0,x=-3/2
x(2-3x)+3x=2x(2-3x)=2-3x(x-1)(2-3x)=0x=1或者x=2/3````````````````````````````````````````再问:请问第三步是怎么得到
解3x²=-7x3x²+7x=0x(3x+7)=0∴x=0或3x+7=0∴x=-7/3或x=0