因式分解(x^2 3x-3)(x^2 3x 1)-5
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(x-1)(x-3)+7=x²-4x+3+7=x²-4x+10=(x-2)²+6=(x-2+√6)(x-2-√6)再问:题目错了,不过还得谢谢你(x-1)(x-3)+1
(x-3)(x+1)再问:用因式分解做X²-x再答:亲记得加分哦~x(x-1)再问:x²-2x+1再答:(x-1)^2再问:x+x²-1/2x-x+1/x²再答
原式=-(x-y)³(x-y-1)
2x^2+3x-2=(2x-1)(x+2)十字相乘.或者:2x^2+3x-2=2x^2+4x-x-2=2x(x+2)-(x+2)=(x+2)(2x-1)
(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.(x+y)^2-(x+y)^3=(x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、(x
3x*x+11x+10=(3x+5)(x+2)
(x-1)(x-2)(x-3)(x-4)-24=[(x-1)(x-4)][(x-2)(x-3)]-24=[(x^2-5x)+4][(x^2-5x)+6]-24=(x^2-5x)^2+10(x^2-5x
3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)
(x+1)(x-3)=x²-3x+x-3=x²-2x-3
(x-3)(x+2)+6x=x^2-x-6+6x=x^2+5x-6=(x-1)(x+6)
x^3-3x+2=x^3-x-2x+2=x(x^2-1)-2(x-1)=x(x-1)(x+1)-2(x-1)=(x-1)(x^2+x-2)=(x-1)(x-1)(x+2)=(x-1)^2(x+2)
如果题目是x四次+3x³+x²-3x-2=(x四次-1)+(3x³-3x)+(x²-1)=(x²-1)(x²+1+3x+1)=(x+1)
实数范围内不能分解
(x-3)^3-4(x-3)=(x-3)[(x-3)^2-2^2]=(x-1)(x-3)(x-5)
(x+1)(x+3)(x+5)(x+7)+15=[(x+1)(x+7)][(x+3)(x+5)]+15=(x^2+8x+7)(x^2+8x+15)+15=(x^2+8x+7)[(x^2+8x+7)+8
(x+1)(x+2)(x+3)(x+4)-24因式分解原式=[(x+1)(x+4)]*[(x+2)(x+3)]-24=(x^2+5x+4)*(x^2+5x+6)-24设A=x^2+5x,则原式=(A+
x^4-3x^3+1x1=2.96149962551495.x2=0.764826485929182.
(x-1)(x-3)(x-5)(x-7)-9=(x-1)(x-7)(x-3)(x-5)-9=(x²-8x+7)(x²-8x+15)-9=(x²-8x)²+22(
原式=x(x+1)