因式分解-4x的三次方y 8x的平方-搜答案-智慧作业帮

X³+Y³=(X+Y)(X²-XY+Y²)

x³-x²-4x+4=(x³-x²)-(4x-4)=x²(x-1)-4(x-1)=(x²-4)(x-1)=(x+2)(x-2)(x-1)很高

原式=(x^4+xy³)-(2y^4+2x³y)=x(x³+y³)-2y(x³+y³)=(x-2y)(x³+y³)=(x

(x+y)^3+(z-x)^3-(y+z)^3=[(x+y)^3-(y+z)^3]+(z-x)^3=[(x+y)-(y+z)][(x+y)^2+(x+y)(y+z)+(y+z)^2]+(z-x)^3=

x^4-x^3-5x^2-6x-4=(x^2+ax+b)(x^2+cx+d)=x^4+(a+c)x^3+(ac+b+d)x^2+(ad+bc)x+bd由于x的相同次数的项的系数要相等所以a+c=-1,

/>（3x+1)^3-x^3=(3x+1-x)[(3x+1)^2+x(3x+1)+x^2]=(2x+1)(9x^2+6x+1+3x^2+x+x^2)=(2x+1)(13x^2+7x+1)(a-b-4)

3x²+3x+13²-4*3*1=-3＜0故不能因式分解

4x³-xy²=x(4x²-y²）=x(2x-y)(2x+y)

再问：谢谢大神再答：有问题继续密我

=（y-x)^3-(y-x)=(y-x)[(y-x)^2-1]=(y-x)(y-x+1)(y-x-1)

1x³-2x²-7x-4=x³+2x²+x-4x²-8x-4=x(x²+2x+1)-4(x²+2x+1)=(x-4)(x²

=xy(4x²+4xy+y²)=xy(2x+y)²

x的三次方+8y三次方=(x+2y)(x平方-2xy+4y平方）

(3x+1)^3-x^3=(3x+1-x)[(3x+1)^2+x^2+x(3x+1)]=(2x+1)[9x^2+6x+1+x^2+3x^2+x]=(2x+1)[13x^2+7x+1]

x³y-xy³=xy(x²-y²)=xy(x+y)(x-y)

x/4+x^3-x^2=(x/4)(1+4x^2-4x)=(x/4)(2x-1)^2

(x-y)^4=x^4+y^4+6x^2y^2-4x^3y-4y^3xx^4-2x^2y^2-4xy^3+4x^3+y^2（4x^2+3/4y^2)=1/4[(4x^4+4y^4+24x^2y^2-1

4x的三次方+4x²+x=X(4X平方+4X+1)=X(2X+1)平方

2x减x的三次方=2x-x³=x(2-x²)=x(√2+x)(√2-x)

您好：x的三次方(y-x)的三次方-(x-y)的三次方=x的三次方(y-x)的三次方+(y-x)的三次方=（x³+1）(y-x)³=（x+1）（x²-x+1）(y-x)&