因式分解:8x的三次方 y的三次方-搜答案-智慧作业帮

X³+Y³=(X+Y)(X²-XY+Y²)

1、(x+y)乘(x-y)的三次方+(x+y)的三次方乘(y-x)=（x+y)(x-y)((x-y)²-(x+y)²)=（x+y)(x-y)(x-y+x+y)(x-y-x-y)=-

(x+y+z)^3-x^3-y^3-z^3=(x+y+z)^3-x^3-(y^3+z^3)=(x+y+z-x)[(x+y+z)^2+x(x+y+z)+x^2]-(y+z)(y^2-yz+z^2)=(y

x³+x²y+xy²+y³=x²(x+y)+y²(x+y)=(x+y)(x²+y²)

8(x+y)的三次方+1=[2(x+y)+1][4(x+y)²-2（x+y）+1]=(2x+2y+1)(4x²+8xy+4y²-2x-2y+1)如果本题有什么不明白可以追

(x-2y)³+8x²y-16xy=(x-2y)³+8xy(x-2y)=(x-2y)[(x-2y)²+8xy]=(x-2y)[x²-4xy+4y

原式=(x^4+xy³)-(2y^4+2x³y)=x(x³+y³)-2y(x³+y³)=(x-2y)(x³+y³)=(x

(x+y)^3+(z-x)^3-(y+z)^3=[(x+y)^3-(y+z)^3]+(z-x)^3=[(x+y)-(y+z)][(x+y)^2+(x+y)(y+z)+(y+z)^2]+(z-x)^3=

x三次方+8=（x+2)(x^2-2x+4)

再问：谢谢大神再答：有问题继续密我

=（y-x)^3-(y-x)=(y-x)[(y-x)^2-1]=(y-x)(y-x+1)(y-x-1)

x³+y³=x³+x²y-x²y-xy²+xy²+y³=x²(x+y)-xy(x+y)+y²(x+y

=xy(4x²+4xy+y²)=xy(2x+y)²

x的三次方+8y三次方=(x+2y)(x平方-2xy+4y平方）

x³y-xy³=xy(x²-y²)=xy(x+y)(x-y)

添项减项法y³+7y²-8=y³-y²+8y²-8=y²(y-1)+8(y²-1)=y²(y-1)+8(y+1)(y-1

您好：x的三次方(y-x)的三次方-(x-y)的三次方=x的三次方(y-x)的三次方+(y-x)的三次方=（x³+1）(y-x)³=（x+1）（x²-x+1）(y-x)&

解x^3-8=x^3-2^3=(x-2)(x^2+2x+4)公式a^3-b^3=(a+b)(a^2+ab+b^2)再问：谢谢🌹🌹🌹再答：不用客气

x³－3x²y＋3xy²－y³＝﹙x³－y³﹚－3xy﹙x－y﹚＝﹙x－y﹚﹙x²＋xy＋y³﹚－3xy﹙x－y﹚＝﹙x

原式=2³+(x/3)³=(2+x/3)(4-2x/3+x²/9)再问：8+x³/27=2³+(x/3)³=(2+x/3)(4-2x/3+x