5ab-4a²b–8ab²+3ab-ab²–4a²b

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如a-b=4,ab=1,则(2-ab+2a+5b)-(3ab+2b-2a)-(3a+4b-ab)=

(2-ab+2a+5b)-(3ab+2b-2a)-(3a+4b-ab)=2-ab+2a+5b-3ab-2b+2a-3a-4b+ab=a-b-4ab+2=4-4+2=2

化简:a-(3ab+b)+(3a-4b-ab)

a-(3ab+b)+(3a-4b-ab)=a-3ab-b+3a-4b-ab=4a-4ab-5

5ab^2-7a^2b-8ab^2-3a^b合并同类项

5ab^2-7a^2b-8ab^2-3a^2b=-3ab^2-10a^2

已知a-b=5,ab=-4,求代数式5a^2b(a-b)-3ab(b-a)^2+5ab^2(b-a)的值

原式=5a²b(a-b)-3ab(a-b)²-5ab²(a-b)=ab(a-b)[5a-3(a-b)-5b]=ab(a-b)(5a-3a+3b-5b)=ab(a-b)(2

化简求值:3a²b-[2ab²-2(-a²b+4ab²)]-5ab²,

3a²b-[2ab²-2(-a²b+4ab²)]-5ab²=3a²b-[2ab²+2a²b-8ab²]-5ab

5a²-2ab-2a²-(4a²-2ab+b²)=

解题思路:先去括号,再合并同类项即可,注意去括号时符号的变化解题过程:

先化简再求值﹕若a-b等于5,ab等于-5,求(2a+3b-2ab)-(a+4b+ab)-(3ab-2a+2b)

(2a+3b-2ab)-(a+4b+ab)-(3ab-2a+2b)=2a+3b-2ab-a-4b-ab-3ab+2a-2b=3a-3b-5ab=3(a-b)-5ab=3x5-5x(-5)=40

已知正数ab满足ab^2=3,a^4b^5=6,那么a^7b^8=?

a^4b^5/ab^2=6/3a^3b^3=2a^7b^8=a^6b^6xab^2=(a^3b^3)^2xab^2=2^2x3=12手机提问的朋友在客户端右上角评价点【满意】即可.

先化简,再求值5ab+4a+7b+6a-3ab-4ab+3b,其中a+b=6,ab=3

5ab+4a+7b+6a-3ab-4ab+3b=(5-3-4)ab+(4+6)a+(7+3)b=10a+10b-2ab=10(a+b)-2ab=10×6-2×3=54

化简:5(3a^2b-ab^2)-4(-ab^2+3a^2b)

5(3a^2b-ab^2)-4(-ab^2+3a^2b)=15a²b-5ab²+4ab²-12a²b=3a²b-ab²

已知a+b=17,ab=10,求代数式(5ab+4a+7b)+(6a-3ab)-(4ab-3b)

(5ab+4a+7b)+(6a-3ab)-(4ab-3b)=5ab+4a+7b+6a-3ab-4ab+3b=-2ab+10a+10b=-2ab+10(a+b)∵a+b=17,ab=10∴原式=-2×1

若a+b=3,ab=-2,求(5a-5b-ab)-(4a-6b-3ab)

(5a-5b-ab)-(4a-6b-3ab)=5a-5b-ab-4a+6b+3ab=a+b+2ab=3-2x2=-1

已知a-b=5,ab=-1,求代数式(22a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)的值.

(22a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)=22a+3b-2ab-a-4b-ab-3ab-2b+2a=23a-3b-5ab题目抄差了!(22a+3b-2ab)应该是(2a+3

已知a+b=-4,ab=-5,则2(ab-3a)-3(2b-ab)的值为

2(ab-3a)-3(2b-ab)=2ab-6a-6b+3ab=5ab-6(a+b)=5*(-5)-6*(-4)=-25+24=-1

(2a-5b+3ab)+(3a-b)-(8a-9b+ab),其中a-b=4,ab=3

原式=(2a-2b+3ab-3b)+(a-b+2a)-(8a-8b+ab-b)=8+9-3b+4+2a-32+3+b=-8+2a-2b=0还可以解出a和b的值带入

已知:a-b=4,ab=3,求多项式(2a+5b-3ab)-(a+6b-ab)-(2ab+2b-2a)的值

(2a+5b-3ab)-(a+6b-ab)-(2ab+2b-2a)=2a+5b-3ab-a-6b+ab-2ab-2b+2a=3a-3b-4ab=3(a-b)-4ab=12-12=0

合并同类项: -5a^b+6ab^-4ab-2a^b+4ab+3

-5a^2b+6ab^2-4ab-2a^2b+4ab+3=-5a^2b-2a^2b+6ab^2-4ab+4ab+3=(-5-2)a^2b+6ab^2+3=-7a^2b+6ab^2+36x+2x^2-3

合并同类项:-5a^b+6ab^-4ab-2a^b+4ab+3

(1)6x+2x-3x+x+1=6x+1其中x=5原式=30+1=31(2)1/3m-3/2n-5/6n-1/6m=1/6m-14/6n=6/1m-7/3n其中m=6,n=3原式=1-7=-6第二题一

1.(4/3a^2b^2-2ab)*1/2ab 2.-2a^2*(-1/2ab+b^2)-5a*(a^2b+ab^2)

(4/3a^2b^2-2ab)*1/2ab=2/3ab-1-2a^2*(-1/2ab+b^2)-5a*(a^2b+ab^2)=a^3b-2a^2b^2-5a^3b-5a^2b^2=-4a^3b-7a^