5a^3b(-3b)^2 (-6ab)^2

(b-a)^5(a-b)^m+(a-b)^(m+3)(b-a)^2=-(a-b)^5(a-b)^m+(a-b)^(m+3)(a-b)^2=-(a-b)^(5+m)+(a-b)^(m+3+2)=-(a-

令x=a+by=a-b则5x-3y=2(1)2x+5y=7(2)(1)×5+(2)×325x+6x=10+2131x=31x=1y=(5x-2)/3=1所以a+b=1a-b=1相加2a=2所以a=1b

a-b=5ab=-6(a-b)^2=25a^2-2ab+b^2=25a^2-2*(-6)+b^2=25a^2+b^2=13(a+b)^2=a^2+b^2+2ab=13+2*(-6)=1(a+b)=±1

(a-b)^m(a-b)[2(b-a)]^3[(b-a)^5]^2÷(a-b)^m=(a-b)[-8(a-b)^3](a-b)^10=-8(a-b)^14

=24*(a+2b)^4

（a-b)-3a+3b=（a-b）-3（a-b）=（a-b）（a-b-3）(a+b)(a-b)-2b(3a-5b）=a-b-6ab+10b=a-6ab+9b=（a-3）补充：结果是（a-3b）不好意思

方法：提取公因式法,(a-2b)是它们共有的因子,提出来后再合并剩下的部分即可＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝(a-2b)(2a+3b)-2(2b-a)(5a-b)=(a-2b)(2a+3b)+2(

（3a+2b)(6a-5b)(2b-3a)(5a+6b)=(2b+3a)(2b-3a)(6a-5b)(6a+5b)=(4b²-9a²)(36a²-25b²)=3

|a-1|+b^2=6b-9|a-1|+b²-6b+9=0|a-1|+（b-3）²=0∴a=1,b=3（2a-b)^2-(2a+b)(a-b)-3(a-3b)(a+3b)=（4a&

(a-b)^m*(a-b)*[2(b-a)^3*(b-a)^5]^2/(a-b)^m=(a-b)*[2(b-a)^8]^2=(a-b)*4(a-b)^16=4(a-b)^17如果本题有什么不明白可以追

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原式=[(3a)²-(2b)²-(5a²-2ab+10ab-4b²)]/(a-2b)=(9a²-4b²-5a²-8ab+4b

a+2b=5(1)b+3a=6(2)(1)×7+(2)7a+14b+b+3a=35+610a+15b=41两边除以52a+3b=41/5

(3a-6b)/(a+b)-(5a-6b)/(a-b)-(4a-5b)/(a+b)-(7a-8b)/(a-b)=(3a-6b)/(a+b)-(4a-5b)/(a+b)-(5a-6b)/(a-b)-(7

8a+2b+(5a-b)=8a+2b+5a-b=13a+b(5a-3b)-3(a平方-2b)=5a-3b-3a²+6b=5a+3b-3a²

A是165B是11C是132D是48

a²-b²=1/3(a-b)(a+b)=1/3(a+b)/6=1/3a+b=2a(3a+5b)-(a-b)(a+2b)=3a²+5ab-a²-ab+2b

(a-b)^m+3(b-a)^2(a-b)^m(b-a)^5=(a-b)^m+3(b-a)^7(a-b)^m=(a-b)^m-3(a-b)^7(a-b)^m=(a-b)^m-3(a-b)^(m+7)=

化简的=(3a-6b-4a+5b)/(a+b)-(5a-6b-7a+8b)/(a-b)=(-a-b)/(a+b)-(-2a+2b)/(a-b)=-1-(-2)=1

[(a+2b)(a-2b)-(2a-b)^2+(3a-b)(3a-5b)]÷2a=(a²-4b²-4a²+4ab-b²+9a²-18ab+5b