1 2x-y=1 3z
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3x+2y+z=133x+3y+6z=21得y+5z=812x+2y+4z=142x+3y-z=12得y-5z=-22由1.2得y=3z=1x=2
[x+(z-y)][x-(z-y)]=x-(z-y)记得采纳啊
第一式X2再减第二式,消去x,依此类推再问:不晓得咋做!再问:你做出来要得不谢谢再答:由4,5解y,z最后求x再答:
答案为x=2,y=3,z=1;解答过程为:1式与3式相加可得5x+5y=25,算出x+y=5,代入2式得z=1,再把z=1代入可得x=2,y=3;要采纳哦!
-x+2y+3z=12(1)2x-2y+5z=13(2)3x+2y+z=10(3)(1)+(2)x+8z=25(4)(2)+(3)5x+6z=23(5)(4)*-5+(5)-34z=-102z=3将z
第一题3x-y+z=3①;2x+y-3z=11②;x+y+z=12③;①减③2X-2Y=-9④;3倍的③即3X+3Y+3Z=36⑤;⑤加②5X+4Y=47⑥;2倍的④4X-4Y=-18⑦;⑥式加⑦9X
x=4y=1z=-1需要详细步骤么?再问:要再答:3x+2y+z=13(1)x+5y+2z=7(2)2x+3y-z=12(3)(1)+(3)=5x+5y=25(2)+2(3)=x+5y+2z=4x+6
(z),(x,y)(5x+7y=31,5x+3y=19)(x=2,y=3)(x=2,y=3,z=1)
5x+5y=25and5x+7y=31得:y=3,x=2将x=2,y=3带入原方程(随便哪一个)得:z=1所以:x=2,y=3,z=1再答:呵呵,助人为乐~
x+y+z-6=02x+3y-z-12=02x-y-z=0组成方程组再解x=2y=3z=1
3x+2y+z=13①x+y+2z=7②2x+2y-z=12③①-3*②得-y-5z=-8④2*①-3*③得-2y+5z=-10⑤2*④-⑤得-15z=-6z=2/5代入z到④,得y=6代入y和z到①
3x+2y+z=13(1)x+y+2z=7(2)2x+3y-z=12(3)(1)-2(2)等于x-3z=-1(4)(3)-3(2)等于-x-7z=-9化简为x+7z=9(5)(4)(5)联立(5)-(
3x+2y+z=13❶x+y+2z=7❷2x+3y-z=12❸❶+❸得5x+5y=25则x+y=5代入❷得5+2z=
x(x+y+z)=6(1)y(x+y+z)=12(2)z(x+y+z)=18(3)(1)/(2)x/y=1/2y=2x(1)/(3)x/z=1/3z=3xx(x+2x+3x)=66x^2=6x=1y=
最好的方法:3X+2Y+Z=13①X+Y+2Z=7②2X+3Y-Z=12③先将三个式子相加得6X+6Y+2Z=323X+3Y+Z=16④④-①得Y=16-13=3将Y=3带入①得3X+Z=7⑤将Y=3
1,﹛2x+y+z=-26,x+2y+z=-30,x+y+2z=-28,4x+4y+4z=-84,x+y+z=-21,﹛x=-5,y=-9,z=-7,2,﹛5x+2y+z=12,4x+3y+z=13,
X+Y=5(1)Y+Z=12(2)X+Z=13(3)(3)-(2)得X-Y=1(4)(1)+(4)得2X=6X=3Y=2Z=10
1.x=10,y=9,z=22.x=3,y=2,z=13.x=30,y=20,z=16.
X+Y+Z
3元一次方程,好像是初一的问题哦.根据前面两个等式可以得出x=3zy=z(平方)/32x+3y+4z=2*(3z)+3*(z方/3)+4z现在变成了一元二次方程,你应该会解吧.