1 2x-y=1 3z,x-y-1=z,4x-5y 3z=5

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3x+2y+z=13 x+y+2z=7 2x+3y-z=12 x=?y=?z=?

3x+2y+z=133x+3y+6z=21得y+5z=812x+2y+4z=142x+3y-z=12得y-5z=-22由1.2得y=3z=1x=2

已知 x,y,z都是正实数,且 x+y+z=xyz 证明 (y+x)/z+(y+z)/x+(z+x)/y≥2(1/x+1

1/x=p1/y=q1/z=rpq+qr+pr=1(y+x)/z+(y+z)/x+(z+x)/y≥2(1/x+1/y+1/z)^2为(pq+qr+pr)[r/p+r/q+q/r+q/p+p/r+p/q

(x+y-z)(x-y+z)=

[x+(z-y)][x-(z-y)]=x-(z-y)记得采纳啊

一条分式数学题已知x y z满足x/x+y + y/z+x + z/x+y =1,求x²/x+y + y&su

因为x/y+z+y/z+x+z/x+y=1所以x/y+z=1-y/z+x-z/x+y,两边同乘以x得x^2/y+z=x-xy/z+x-xz/x+y同理y^2/x+z=y-xy/z+y-yz/x+y,z

{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z

答案为x=2,y=3,z=1;解答过程为:1式与3式相加可得5x+5y=25,算出x+y=5,代入2式得z=1,再把z=1代入可得x=2,y=3;要采纳哦!

解下列方程组(1)3x-y+z=3 2x+y-3z=11 x+y+z=12(2)5x-4y+4z=13 2x+7y-3z

第一题3x-y+z=3①;2x+y-3z=11②;x+y+z=12③;①减③2X-2Y=-9④;3倍的③即3X+3Y+3Z=36⑤;⑤加②5X+4Y=47⑥;2倍的④4X-4Y=-18⑦;⑥式加⑦9X

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,

x+y+z-6=02x+3y-z-12=02x-y-z=0组成方程组再解x=2y=3z=1

已知 x/(y+z)+y/(z+x)+z/(x+y)=1

因为x/y+z+y/z+x+z/x+y=1所以x/y+z=1-y/z+x-z/x+y,两边同乘以x得x^2/y+z=x-xy/z+x-xz/x+y同理y^2/x+z=y-xy/z+y-yz/x+y,z

解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18

x(x+y+z)=6(1)y(x+y+z)=12(2)z(x+y+z)=18(3)(1)/(2)x/y=1/2y=2x(1)/(3)x/z=1/3z=3xx(x+2x+3x)=66x^2=6x=1y=

已知{x:y:z=1:2:3,x+y+z=12,求x、y、z的值

x:y:z=1:2:3,x=k,y=2k,z=3kx+y+z=k+2k+3k=6k=12k=2x=2,y=4,z=6

已知x、y、z满足|4x-4y+1|+152y+z+(z−12)

根据题意得,4x-4y+1=0,2y+z=0,z-12=0,解得x=-12,y=-14,z=12,∴x+z-y=-12+12-(-14)=14,∴x+z−y=14=12.故答案为:12.

已知x,y,z满足x/(y+z)+y/(z+x)+z/(x+y)=1,求代数式x2/(y+z)+y2/(x+z)+z2/

x/(y+z)+y/(z+x)+z/(x+y)=1所以x/(y+z)=1-[y/(z+x)+z/(x+y)]y/(z+x)=1-[x/(y+z)+z/(x+y)]z/(x+y)=1-[x/(y+z)+

已知实数x,y,z满足x/(y+z)+y/(z+x)+z/(x+y)=1,求x2/(y+z)+y2/(z+x)+z2/(

等于0.x/(y+z)=1-[y/(z+x)+z/(x+y)]y/(z+x)=1-[x/(y+z)+z/(x+y)]z/(x+y)=1-[x/(y+z)+y/(z+x)]x2/(y+z)+y2/(z+

x:y=1:2 z:x=3:1 x +y+z=12

由x:y=1:2,得y=2x,由z:x=3:1,得z=3x,代人x+y+z=12中,得,x+2x+3x=12,解得,x=2,所以y=2x=4,z=3x=6

3x+2y+z=13 (1) x+y+2z=7 (2) 2x+3y-z=12 (3)

首先(1)+(3):5x+5y=25,x+y=5,x=5-y(4),将(4)带入(2):5-y+y+2z=7,z=1.将(4)带入(1):3x+2y=12(5).联解(4)(5),可得x=2.y=3.

x+y+z=1 求xyz/(x+y)(y+z)(z+x)的最大值

x+y大于等于2倍根号下xy同理x+z大于等于2倍根号下xzz+y大于等于2倍根号下zy所以(x+y)(y+z)(z+x)大于等于8xyz当取到8xyz时分数值最大为1/8此时x=1/3y=1/3z=

1,{2x+y+z=-26,x+2y+z=-30,x+y+2z=-28 2,{5x+2y+z=12,4x+3y+z=13

1,﹛2x+y+z=-26,x+2y+z=-30,x+y+2z=-28,4x+4y+4z=-84,x+y+z=-21,﹛x=-5,y=-9,z=-7,2,﹛5x+2y+z=12,4x+3y+z=13,

1.x+y+z=21,x-y=1,2x+z-y=13.2.3x+2y+z=13,x+y+2z=7 ,2z+3y-z=12

1.x=10,y=9,z=22.x=3,y=2,z=13.x=30,y=20,z=16.

X+Y+Z=?

X+Y+Z

f(x,y,z,w)=x*(x+y)*(x+y+z)*(x+y+z+w)

f=x+1f+u=2x+3f+u+c=3x+8f+u+c+k=4x+15f(f,u,c,k)=(x+1)(2x+3)(3x+8)(4x+15)