7y分之12x除以8x^2y-搜答案-智慧作业帮

原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]=[xy/(x+y)]×xy/(x+y)=x²y²/(x+y)²

原式=-3xy^2*144y^2/x^2*x^3/216y^6=-2*1/y^2=-2/y^2

y=[x/(x-2)-x/(x+2)/2x/(2-x)=4x/(x-2)(x+2)*(2-x)/2x=-2/(x+2)y的值是整数,x+2=1,-1,2,-2x=,-1,-3,0,-4

【x-y-(x-y分之4y平方)】【x+y-(x+y分之4x平方)】除以【3(x+y)-x-y分之8xy】=（x-y-x+4y)(x+y-x-4x/y)/(3x+3y-x-8x)=3y*(y-4x/y

[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]/4x=[x^2-4y^2-x^2-4y^2+4xy+8xy+8y^2]/4x=12xy/4x=3y

解原式=2(x-y)/(x+y)-(x+y)/3(x-y)=6(x-y)(x-y)/[3(x+y)(x-y)]-(x+y)x+y)/[3(x-y)(x+y)]=5(x-y)(x-y)/[(x+y)(x

自己想

1.7y分之12x除以8x的平方Y=12x/7y×1/8x²y=3/14xy²2.x平方-1分之x的平方-2x+1除以x的平方+x分之x-1=(x-1)²/(x+1)(x

x平方+y平方+2xy分之x平方-4y平方除以x平方+xy分之2y+x=(x-2y)(x+2y)/(x+y)²·x(x+y)/(x+2y)=x(x-2y)/(x+y)

1.计算：x-y分之x+y+y-3分之2x=(x+y)/(x-y)+2x/(y-3)=((x+y)(y-3)+2x(x-y))/(x-y)(y-3)=(xy-3x+y^2-3y+2x^2-2xy)/(

【(x-y)^2+(x+y)(x-y)】除以2x=(x-y)*(x-y+x+y)/2x=(x-y)*2x/2x=x-y

(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)

（1）=x平方-y平房分之x(x+y)-y(x-y)+2xy=（x+y）*（x-y）分之（x+y）的平方=x-y分之x+y（2）=a-1分之2-a-1分之a+1=-1

[3x分之2-（x+y分之2）乘以[3x分之x+（y-x^2-xy）]除以x分之x-y{2/3x-2/(x+y)*[x/3x+(y-x²-xy)]}÷(x-y)/x题目错了吧?再问：{3x分

(3x-4y)÷(2x+y)=1/2所以2x+y=2(3x-4y)=6x-8y4x=9y所以x/y=9/4

楼上做得不对!x^2+4y^2-2x+8y+5=0x^2-2x+1+4y^2+8y+4=0(x-1)^2+4(y+2)^2=0x=1y=-2原式解得x^2+y^2分之y代入得（负二分之一）如果有问题、

解题思路：这是分式的除法，先变乘然后把分子分母因式分解，最后进行约分化成最简分式。解题过程：

是这样的形式吗?[x/（x+y）+2y/（x+y）]×[xy/（x+y）]÷（1/x+1/y）一:原式=（x+2y）/（x+y）×[xy/（x+2y）]÷[（x+y）/xy]=x²y&sup

原式即为A*(x+2y)^2/(x-y)(x+y)=1即A*16/3=1∴A=3/16很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

6/√(x+y)÷12/√(x-y)=√(x-y)/[2√(x+y)]=√(x^2-y^2)/[2(x+y)]