作业帮1-m² 10mn
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解啊.:-2(mn-3m的平方)-{m的平方-5(mn-m的平方)+2mn}=-2(mn-3m²)-(m²-5mn+5m²+2mn)=-2mn+6m²-6m&#
原式=-2mn+6m²-m²+5（mn-m²）-2mn,=-2mn+6m²-m²+5mn-5m²-2mn,=mn,当m=1,n=-2时,原式
(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)先去括号=2mn+2m+3n-3mn-2n+2m-m-4n-mn合并同类项=-2mn+3m-3n=-2mn+3(m-n)把m-n=2,
1.m²+5n-mn-5m=（m²-mn）+（5n-5m）=m(m-n)-5(m-n)=(m-5)(m-n)2.a3+a²b-4ab²-4b3=a²(
再答：求采纳！再问：。。。。。
先合并同类项,得3(m-n)-6mn+9,代入已知数据,有结果27
(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=(-2mn-3mn-mn)+(2m+2m-m)+(3n-2n-4n)=-
再答：原式=2m(n+1)-(n+1)2=2(m-1)(n+1)
你的符号用的不对,m分之一应该是1/m,不是m/1原式=(m^2+n^2)/(m-n)^2-(2/mn)/(1/m-1/n)^2=(m^2+n^2)/(m-n)^2-(2/mn)*[mn/(m-n)]
-2mn+2m+3n-3mn-2n+2m-4n-m-mn=-6mn+3m-3n=-6mn+3(m-n)=6+9=15
根据题意绝对值和完全平方非负所以mn-1=0m-n-2=0mn=1m-n=2（-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-m
-2(mn-3m平方)-{m平方-5(mn-m平方)+2mn},其中m=1,n=-2=-2mn+6m^2-m^2+5(mn-m^2)-2mn=-2mn+6m^2-m^2+5mn-5m^2-2mn=mn
记得看回答时间复制者死首先求出m与nm²-2m+10=6n-n²m²-2m+10-6n+n²=0(m²-2m+1)+(n²-6n+9)=0（
原式=-4m³+2m³n-2m²没了……
m^2+n^2=(m+n)^2-2mn=10^2-2x24=100-48=52(m-n)^2=(m+n)^2-4mn=10^2-4x24=100-96=4
原式=3m^2-3mn+6n^2-2mn+2m^2-2n^2+5mn-4n^2+1=5m^2+1再问：（2x-3y+z)-3(x-2(-z+(x-y))-(3y-5z)再答：原式=2x-3y+z-3(
已知mn=-1,m-n=4则(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)=-2mn+m+n-3mn-5n+5m-m-4n+3mn=-2mn+5m-8n=2+20-3n=22-3n
(-2mn)^3(mn+1/2)(m^2n^2-1/2mn+1/4)=(-2mn)^3(mn+1/2)(mn-1/2)^2=(-2mn)^3(m^2n^2-1/4)(mn-1/2)=(-2mn)^3[
(m-2n)/(m^2-2mn)=(m-2n)/[m(m-2n)]=1/m