9分之2x加x=45

(x^2-3x+1)/(x^2-4)=30/(x+2)(x^2-3x+1)/(x-2)=30x^2-3x+1=30x-60x^2-33x+61=0x=(33±√1333)/2

(x^2-3x+1)/(x^2-4)=30/(x+2)(x^2-3x+1)/(x-2)=30x^2-3x+1=30x-60x^2-33x+61=0x=(33±√1333)/2

你这个题目稍微有点乱啊……如果我看的不错的话应该是这样——（5x+2)/(x^2+x)=3/(x+1)其中x不等于0和-1交叉相乘得（5x+2)(x+1)=3(x^2+x)整理得2x^2+4x+2=0

答：1）x/(x^2-x)+2=2x/(x+1)1/(x-1)=2x/(x+1)-2=-2/(x+1)-2x+2=x+13x=1x=1/3经检验,x=1/3是原分式方程的解2）x/(x+1)-1=3/

x-3分之2x=123分之1x=12x=12×3x=36x加7分之2x=187分之9x=187分之x=2x=149分之4x-3=139分之4x=13+39分之4x=169分之x=4x=36再问：X-3

2x^2-6x+3=02x-6+3/x=02x+3/x=6平方(2x+3/x)^2=364x^2+9/x^2+12=364x^2+9/x^2=24

f(x)=[2x+(1-2x)][2/x+9/(1-2x)]=13+18x/(1-2x)+2(1-2x)/x0013+18x/(1-2x)+2(1-2x)/x>=13+2√[18x/(1-2x)*2(

移项左边是+2分之9则移到右边是-2分之9所以x=12-2分之9x=2分之13

2/(x+3)(x-3）+(x-2)/x(x-3)=1/x(x+3)两边乘x(x+3)(x-3)2x+x^2+x-6=x-3x^2+2x-3=0(x+3)(x-1)=0x+3在分母,不等于0所以x=1

设x-2为A,将A代入式子得,A分之x+3A分之4x=2,然后根据正常的解方程步骤算出结果

x+2分之2x减2=x-2分之1加4-x分之x+14左右两边同×（x+2）(x-2)(4-x)得：（2x-2）(x-2)(4-x)=(x+2)(4-x)+(x+14)(x+2)(x-2)2(x-2)&

每个分式减去1(x-4-x+5)/(x-5)+(x-8-x+9)/(x-9)=(x-7-x+8)/(x-8)+(x-5-x+6)/(x-6)1/(x-5)+1/(x-9)=1/(x-8)+1/(x-6

1+1/(x+2)+1+1/(x+3)=1+1/(x+4)+1+1/(x+1)1/(x+2)+1/(x+3)=1/(x+4)+1/(x+1)1/(x+3)-1/(x+4)=1/(x+1)-1/(x+2

2x=4x-82x=8x=42分之x-6=3分之xx/2-x/3=6x/6=6x=363（2x-1)-2(1-x)=06x-3-2+2x=08x=5x=5/8六分之2x加4分之(3-x)=14x+3(

这个,由于没有括号题目不太清楚,是这样吗?x/√3+3/√x+(x^2+9)/3x+(x^2+9)/[2+√(3x)]-2这个没有太多简便方法,直接带进去算就行再问：是根号（3分之x）+根号（x分之3

解方程x+2分之x-2-x的平方分之16=x-2分之x+2详细步骤加检验x+2分之x-2-x的平方分之16=x-2分之x+2解,得：(x-2)/(x+2)-(16/x^2)==(x+2)/(x-2)(

(x+7)/(x+6)+(x+9)/(x+8)=(x+10)/(x+9)+(x+6)/(x+5)1+1/(x+6)+1+1/(x+8)=1+1/(1+9)+1+1/(x+5)1/(x+6)+1/(x+

x/2+x/6+x/12+x/20+x/30=5x(1/2+1/6+1/12+1/20+1/30)=5x(3/6+1/6+1/12+1/20+1/30)=5x(4/6+1/12+1/20+1/30)=

4x=4/9x=4/9*1/4x=1/9再问：x减4分之1x=8分之7再答：再问：6分之5x除4分之3=9分之2。方程。这个弄好就采纳了。谢谢