已知(x减1)(x减2))分之3x减4等于x减一分之a加x减2分之b,求实数ab
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原式=(x^2-1)/x÷(x^2+x)/x^2=(x-1)(x+1)/x*x^2/x(x+1)=x-1当x=2时,原式=2-1=1
x-3=1/xx(x-3)=1x²-3x+2=x(x-3)+2=1+2=3
x=2/(√5-3)=-(3+√5)/2‘分母有理化x+3/2=-√5/2移项(x+3/2)²=5/4两边平方x²+3x+9/4=5/4x²+3x=-1x(x+1)(x+
(x减2)乘(x加5)分之4x加1等于x加五分之a加x减2分之b(4x+1)/(x-2)(x+5)=a/(x+5)+b/(x-2)(4x+1)/(x-2)(x+5)=(ax-2a+bx+5b)/(x-
[(x-1)/2]-(x/3)=13(x-1)-2x=6x=9√x/(x+2)=3/11
x+1/x=√13两边平方x²+2+1/x²=13x²+1/x²=11(x-1/x)²=x²-2+1/x²=11-2=9所以x-1
3x-1<2x+2x<3A={x|3x-1<2x+2}={x|x<3}2(x+1)/3≥6-x/32x+2≥18-x3x≥16x≥16/3B={x|2(x+1)/3≥6-x/3}={x|x≥16/3}
x+1分之3减x-2分之6=(x+1)(x-2)分之x-m(x+1)(x-2)分之(3x-6-6x-6)=(x+1)(x-2)分之x-m(x+1)(x-2)分之(-3x-12)=(x+1)(x-2)分
已知x²-7x-1=0所以x²-1=7x所以x-1/x=7故1/x-x=-7如果不懂,请Hi我,祝学习愉快!
因为:x(x+1)(x+2)(x+3)=x(x+3)(x+1)(x+2)=(x²+3x)(x²+3x+2)而因为x=(√5-3)/2代入x²+3x得x²+3x=
x²-3x=-1即x²+1=3xx+1/x=3
1题目是:x²/(x²-2)=3,求[1/(1-x)-1/(1+x)]/[x/(x²-1)+x]吧?如果是这样,那么由x²/(x²-2)=3得,x
x²-11x+1=0,求x²+1/x²原式/x=x-11+1/x=0x+1/x=11(x+1/x)²=11²x²+2+1/x²=1
由已知条件可得:x-y=-4xy,(也就是在等式两边乘xy后整理,即可),代入所求的式子里分母为-4xy+7xy,即3xy;分子为-4xy-2xy,即-6xy,化简得-2
(x+2)(x+3)分之2x-1等x+2分之a减x+3分之b(2x-1)/[(x+2)(x+3)]=[a(x+3)-b(x+2)]/[(x+2)(x+3)](2x-1)/[(x+2)(x+3)]=[(
根号X-根号X分之一=2二边平方得:x-2根号X*根号1/X+1/x=4即X+1/X=4+2=6平方得:X^2+2+1/X^2=36所以,X^2+1/X^2=34
(x+2/x)=4所以x^2+4+4/x^2=16x^2+4/x^2=12而(x-2/x)^2=x^2-4+4/x^2=8所以x-2/x=±√8=±2√2