已知3x-4y=0,求分式x平方 2xy 3x的平方-y的平方

(x+y-z)/z=(y+z-x)/x=(z+x-y)/y[x+y]/z-1=[y+z]/x-1=[z+x]/y-1[x+y]/z=[y+z]/x=[z+x]/y设[x+y]/z=[y+z]/x=[z

x^2+y^2-6x-8y+25=0x^2-6x+9+y^2-8y+16=0(x-3)^2+(y-4)^2=0∴x=3且y=4y/x-x/y=4/3-3/4=7/12

原式＝(x^2-2x+1)+(y^2-4y+4)=(x-1)^2+(y-2)^2=0,所以x=1,y=2,代入问题得结果为3/2

2x-3y=0所以y=2x/3代入(x^2+xy-y^2)/(2x^2+xy-y^2)得到[x^2+x*2x/3-(2x/3)^2]/[2x^2+x*2x/3-(2x/3)^2]=(x^2+2x^2/

此题做法不止一种,这里给你一个较简单方便的做法如果是填空题,直接把x换成4,y换成3代入即可算出正确答案

再问：化简：（1）【(a+2/a^2-2a）+(8/4-a^2)】除以a-2/a（2）x-3/x^2-1+1/1-x（3）【a-（2a-1/a）除以1-a^2/a^2+a】再答：嗯嗯~~等我一会

令X/3=Y/4=Z/6=KX=3KY=4KZ=6K(X+Y-Z)/(X-Y+Z)=(3K+4K-6K)/(3K-4K+6K)=K/5K=1/5

∵4x-y=0∴y=4x∴(x²+3y)/(2y-3x)=(x²+12x)/(8x-3x)=[x(x+12)]/(5x)=(x+12)/5明白请采纳,有疑问请追问!有新问题请求助,

x^2+y^2-4x-6y+13=0(x^2-4x+4)+(x^2-6y+9)=0(x-2)^2+(y-3)^2=0所以(x-2)^2=0,(y-3)^2=0x-2=0,y-3=0x=2,y=3xy/

x-3y=0x=3y2x+y/x^2-2xy+y^2×(x-y)=(2x+y)/(x-y)^2*(x-y)=(2x+y)/(x-y)=(6y+y)/(3y-y)=7y/2y=7/2

1/x-1/y=3（y-x）/xy＝3y-x＝3xy（4x-5xy－4y）/（3x-2xy-3y）＝（4（x－y）-5xy）/（3（x－y）－2xy）＝(4*-3xy-5xy)/(3*-3xy－2xy

x²+3分之x-2y的值为0∵x²+3>0∴x-2y=0∴x=2yx²-y²分之x²-3xy-4y²=(x-4y)(x+y)/(x+y)(x

(x-2y)^2=0=>x=2y=>(2x-y)/(2x+y)=(4y-y)/(4y+y)=3/5

1.已知：4x^2+12xy+9y^2=0(xy≠0),求分式y/x-x/y的值.4x^2+12xy+9y^2=0(2x+3y)^2=0因为(2x+3y)^2大于等于0所以2x+3y=0x=-3/2y

x-5y=0,x=5y【（3x+y）/（x的2次方-2xy+y的2次方）】×（y-x）=(3x+y)/(y-x)²×(y-x)=(3x+y)/(y-x)=(15y+y)/(y-5y)=-4

x－5y=0x=5y原式=（x-y）平方/（3x+y）(y-x)=(5y-y)平方/（15y+y）(y-5y)=16y平方/-64y平方=-1/4如还有新的问题,请不要追问的形式发送,另外发问题并向我

3X-4y=03x=4yx:y=4:3x=4ay=3a3x²-y²分之x²＋2xy=(16a^2+2x4ax3a)/(3x16a^2-9a^2)=40a^2/39a^2=

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0x=1y=-3(x-y)/(x+y)=4/(-2)=-2

y=4x带入3x-y=3x-4x=-xx+y=x+4x=5x(x+y)/(3x-y)=5x/(-x)=-5