已知a² a=3,求代数式1-a 1-a²xa²-2a 1
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/03 13:38:25
a/(a+1)=√10(a+1)/a=1/√101+1/a=1/√101/a=1/√10-1=(1-√10)/√101-1/a=1-(1-√10)/√10=(√10-1+√10)/√10=(2√10-
2a²-a-2=32a²-a=56a²-3a+1=3(2a²-a)+1=3*5+1=16
a=(根号5)-1a+1=√5a²+2a+1=5∴a²+2a-4=0a^3+2a^2-4a+1=a(a²+2a-4)+1=a×0+1=1
a^2=a+1两边平方a^4=a^2+2a+1=(a+1)+2a+1=3a+2a^5=a*a^4=a(3a+2)=3a^2+2a=3(a+1)+2a=5a+2所以a^5-5a+2=5a+2-5a+2=
∵a²+2a-3=0∴a²+2a=3∴3a²+6a-1=3(a²+2a)-1=3×3-1=9-1=8请点击下面的【选为满意回答】按钮,
a^5-5a+3=a³﹙a²+a-1﹚-a^4+a³-5a+3=a³﹙a²+a-1﹚-a²﹙a²+a-1﹚+2a³-a&
题目写得太乱,我只能按照自己理解的大概进行解答,如果理解错误,请把题目再告诉一下(a-4)/(a^2-9)/1/[(a-3)(a^2+2a-3)]/(a^2-8a+16)=(a-4)(a-3)(a^2
3a^3+(a^2+5)(a^2-1)-5(a+1)(a-1)-6a=a^4+3a^3-a^2-6a=a^4+3a^3+a^2-2a^2-6a=a^2(a^2+3a+1)-2a^2-6a=-2a^2-
由[(a-2)/(a(a+2)-(a-1)/(a+2)²]÷(a-4)/(a+2)=[(a-2)(a+2)/a(a+2)²-a(a-1)/a(a+2)²=(a-4)/a(
已知a²+a-1=0,求代数式a⁵-5a的值由a²+a-1=0,得a₁=(-1+√5)/2=-(1-√5)/2;a₂=(-1-√5)/2=-(1
1.(A-B)+A*A+B*B+AB=(A-B)+A*A-2AB+B*B+3AB=(A-B)+(A-B)(A-B)+3AB=3-根号22.(X-1/X)的平方=X的平方-2+(1/X)的平方=X的平方
(1a+1b)÷a2+2ab+b2a+b=a+bab÷(a+b)2a+b=a+bab÷(a+b)=1ab,当a=-3,b=2时,原式=1−3×2=-16.
解a+a^-1=4(a+1/a)²=16∴a^2+2+1/a^2=16∴a²+1/a²=16-2=14(a²+1/a²)²=196∴a^4+
a^2-a-1=0,∴a²-a=1∴a^3-2a+2010=a³-a²+a²-2a+2010=a(a²-a)+a²-2a+2010=a+a&
(a-4)/(a^2-9)除以1/(a-3)乘以(a^2+2a-3)/(a^2-8a+16)=(a-4)(a-3)(a-1)(a+3)/[(a+3)(a-3)(a-4)²]=(a-1)/(a
a^3+3a^2+a-4=(a^3+a^2-a)+2(a^2+a-1)-2=a(a^2+a-1)-2(a^2+a-1)-2=a×0-2×0-2=-2
a^5-5a+2=a³×a²-5a+2=a³(a+1)-5a+2=a^4+a³-5a+2=(a²)²+a×a²-5a+2=(a+1
a²=a+1所以a⁴=(a²)²=(a+1)²=a²+2a+1=(a+1)+2a+1=3a+2所以原式=3a+2-3a+2=4
|a-1|+|a-2|+|a-3|这些绝对值的值提出都是正数或等于0所以当a大于等于3时a-1+a-2+a-3=03a=6a=2所以当a=2时,|a-1|+|a-2|+|a-3|的最小值=1+0+1=
3a^3-2a^2+a-5=3*(-2)³-2*(-2)²-2-5=-24-8-2-5=-39