已知log2(log3(log4x))=0,且log4(log2y)=1,

0.25^(-1)*(根号3/2)^(1/2）*（27/4）^(1/4)=（1/4）^(-1)*（3/4）^(1/4)*（27/4）^(1/4)=4*3/2=6log2(1/5)*log3(1/8)*

logx/log3=(-1)/[(log3)/log2]logx=-log2=log(1/2)x=1/2原式=1/2*(1-1/2^n)/(1-1/2)=1-1/2^n

不知你的连锁公式是指什么此处可以用换底公式log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log5(7)*6log7(2)=12*log2(3)*

倒数第二个式子分子分母同时提出来一个lg2然后约掉了啊

(log25+log4125)log32/log根号35=(log25+log4125)log32/log325=(log25+log4125)log252=(log25+log25根号5)log25

(log2(5)+log4(125))(log3(2)/log√3(5))=(log2(5)+3/2log2(5))(log3(2)/2log3(5))=5/2log2(5)*1/2log5(2)=5

(log2(5)+log4(125))(log3(2)/log√3(5))=(log2(5)+3/2log2(5))(2log3(2)/log3(5))=5/2log2(5)*2log5(2)=5lo

1、log2(4*5)-(2/2)log2(5)=log2(4)+log2(5)-log2(5)=2；2、换底公式：(lg3/lg2)*(lg5/lg2)*(lg5/lg3)=1；3、log2(5-l

log2[log3(log4x)]=0log3(log4x)=13=log4xx=4^3x=64这个要一步一步看,比如先令t=[log3(log4x)],则log2t=0,t=1,得log3(log4

因为log2[log3(log4x)]=0所以：log3(log4x)=1进一步：log4x=3所以x=4^3=64,.log3[log4(log2y)]=0则有：log4(log2y)=1进一步：l

这个顶多算是一种不规范的简写形式.不过在大多计算器上却都是这么写的,计算器上的log就是lg,估计这里也是仿照这种写法的吧.不推荐多用.

log2(3)+log3(5)+log3(2)=log2(3)+log3(10)=4.2429387700296再问：=1g3/1g2+(lg5+lg2)lg3这个式子最后那个lg3原来是分母，，怎么

原式=（log2(5)+(3/2)log2(5))×log3(2)/(2log3(5))=(5/2)log2(5)))×(1/2)log5(2)=5/4

已知log210=a,换底公式1/lg2=alg2=1/alog310=b1/lg3=blg3=1/blog3(4)=lg4/lg3=2lg2/lg3=2b/a请参考……

等于2/a利用换底公式,log3^2=log2^2/log2^3=a,即log2^3=1/a;log2^9=log2^(3^2)=2log2^3=2*(1/a)=2/a

log3(2)=lg2/lg3=a/blog3(4)=2log3(2)=2a/

没有错...换底公式的运用于逆运用.log(2)(3)xlog(3)(7)=ln3xln7/ln2xln3=ln7/ln2=log(2)(7)

[log3（4）+log根下3（2）][log2(9)+log4(根3)]=[lg4/lg3+lg2/lg根下3][lg9/lg2+lg根3/lg4]=[2lg2/lg3+2lg2/lg3][2lg3

原式=2log5（10乘以0.5）+0+3=2log55+0+3=2+3=5

利用换底公式:log（a）（b）=log(n)(b)/log(n)（a）:log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(3)*[log2(4)/log2(3)