已知因式分解2x(x-y)的m 1次方-搜答案-智慧作业帮

5m(x-y)²+10n(y-x)³=5m(x-y)²-10n(x-y)³=5(x-y)²[m-2n(x-y)]=5(x-y)²(m-2nx

x³+3x-4=(x-1)(x^2+x+4)再问：可以给个过程吗？谢谢再答：定理：当一个只含有一个未知数的多项式当未知数为a时多项式值为0则多项式必有因式（x-a）当x=1时，原式=0∴x&

1.x^4+5x^2-6=(x^2+6)(x^2-1)=(x^2+6)(x-1)(x+1)2.(x+y)(x+y+2xy)+(xy+1)(xy-1)=(x+y)^2+2xy(x+y)+(xy+1)(x

x(x+y)(x-y)-x(x+y)²=x(x+y)(x-y-x-y)=-2xy(x+y)=1再问：第一步到第二步仔细点..谢谢再答：x(x+y)(x-y)-x(x+y)²=x(x

(x+y)的平方-2x-2y-3=(x+y)的平方-2(x+y)-3=(x+y-3)(x+y+1)

因为2x2+3xy-2y2-x+8y-6=(x+2y+m)(2x-y+n)=2x^2+3xy-2y^2+(n+2m)x+(2n-m)y+mn,所以n+2m=-1,2n-m=8,mn=-6,解方程组得m

x(x+y)(x-y)-x(x+y)^2=x(x+y)(x-y-x-y)=-2xy(x+y)=-2*(-1/2)*1=1

x^2-3x+m在整数范围内可以因式分解等价于x^2-3x+m=0解为整数,则9-4m>=0,即m

x（x+y）（x-y）-x（x+y）^2=x（x+y）（x-y）-x（x+y)(x+y)=x(x+y)((x-y)-(x+y))=-2xy(x+y)=-2*(-1/2)*1=1

3m(x-y)-2（y-x）²因为（y-x）²=（x-y）²则提取x-y原式=（x-y）（3m-2x+2y)

已知:xy=1,xy=-2分之1,利用因式分解求x(xy)(x-y)-x(xy)^2的值x(xy)(x-y)-x(xy)^2=x(xy)(x-y-x-y)=-2xy(

比较（k-1）x²-6xy-8y²和(mx+2y)(x-4y)的xy项前面的系数得-6=-4m+2m=2x^2:k-1=mk=3

另一个是X+5,m=6再问：请问过程？

有一个因式是3x-2说明当x=2/3时,代数式的值为03x²+x+m=3*(2/3)²+2/3+m=0所以m=-2此时多项式为3x²+x-2=(3x-2)(x+1)

(x-y)平方+2y(x-y)=(x-y)(x-y+2y)=(x-y)(x+y)

1、m*m/9-mn/3+n*n/4原式=（m／3）²-2×（m／3）n/2+（n/2）²=（m／3-n/2）².2.已知x*x+y*y-2x+1=0,求xy∵x*x+y

已知：x+y=1,xy=-1/2,利用因式分解求：x(x+y)(x-y)-(x+y)的平方的值.x(x+y)(x-y)-x(x+y)^2=x(x+y)(x-y-x-y)=x(x+y)(-2y)=-2x

(x+y)(5m+3n)²-(x+y)(m-n)²=(x+y)[(5m+3n)²-(m-n)²]=(x+y)[(5m+3n)+(m-n)][(5m+3n)-(m

(x+y)²+2x+2y=(x+y)²+2(x+y)=(x+y+2)(x+y)

x(x+y)(x-y)-x(x+y)²=x³-xy²-x³-2x²y-xy²=-2xy(x+y)代入-2*(-1/2)*1=1