已知圆的周长为L,编写c语言程序,计算出它的面积.-搜答案-智慧作业帮

#include#definePI3.1415926doublearea(doubler){returnPI*r*r;}doubleperimeter(doubler){return2*PI*r;}i

#includeintmain(){floatr,s,l;scanf("%f",&r);s=3.14*r*r;l=2*3.14*r;printf("s=%f,l=%f\n",s,l);return0;

voidmain(){floatr,s,l;floatpi=3.1415;printf("输入一个圆的半径:\n");scanf("%f",&r);if(

intarea(intx,inty){returnx*y;}intgri(intx,inty){return2*(x+y);}

#include<stdio.h>double zc(double x, double y){ ret

在vc++编译的.#includevoidmain(){floatl;printf("enterperimeter:");scanf("%f",&l);printf("square=%.2f\n",l

#includevoidmain(){floatC;intF;printf("C\tF\n");for(F=-10;F

#include <stdio.h>int main(){ float c = 6, PI =&

看看这个#include"stdio.h"inthavefive(intx){inta=0;intb=x;for(inti=0;i

#include#definePI3.1415926intmain(){floatL;floatS=0;printf("Pleaseinputcircum:");scanf("%f",&L);S=L*

#includeintmain(){intr=0;floata=0,l=0;scanf("%d",&r);a=r*r*3.14;l=r*2*3.14;printf("面积:%f,周长:%f",a,l)

.就知道一个周长,怎么求面积啊?N种可能啊满意请采纳

#includevoidmain(){doubler,s,l;printf("请输入圆的半径\n");scanf("%lf",&r);s=3.14159*r*r;l=2*3.14159*r;print

圆的周长为C，那么圆心角为n°的弧长l=nC360．故答案为：nC360．

#includeintmain(){intlength,width,perimeter;printf("长：");scanf("%d",&length);printf("宽：");scanf("%d"

简单再问：。。。。这好像不是我要的答案再答：#include"stdio.h"intgcd(intx,inty)//欧几里得辗转相除法求两数的最大的公约数{intm;if(x

#include"stdio.h"#definePI3.141592653//定义πintmain(void){floatC,A,V,r;printf("请输入半径：");//提示输入scanf("%

1.L=（n/360度）*C2.这个题有问题3.3

#include#include#includeusingnamespacestd;intmain(){intr=15,h=3;doublec=2*3.14*r;doubles=pow(r,2)*3.

m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.