已知式子1-2y-y-11 3的值是0
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已知1-2y-(y-11)/3=03-6y-y+11=014=7yy=2所以(3y-1)/4+(2y-1)/3=(3*2-1)/4+(2*2-1)/3=5/4+1=9/4再问:3-6y-y+11=0是
x-2=0x=2;y-1/3=0y=1/32x+3y=2*2+3*1/3=5值为5
3y-1/4-3y-1/3=-7/12
若-2y-[(y-1)/3]+1=0,则1-2y=(y-1)/3,3-6y=y-1,y=4/7;[(3y-1)/4]-(2y/3)-1=3y/4-1/4-2y/3-1=3/7-2*4/(3*7)-5/
[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]/4y=(x^2+y^2-x^2+2xy-y^2+2xy-2y^2)/4y=(2x-y)/2=4022/2=2011
把x-y=-3y+5的左边移到右边:x-y+3y-5=0所以:x+2y-5=0x+2y-1=4
你的式子应该是:4y+3[ky²-2(2y²-3y)-5(y²+2y-3)]-4(1-2y)吧?原式=4y+3ky²-12y²+18y-15y
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|x-3|+|y-1/2|=0因为|x-3|≥0,|y-1/2|≥0所以|x-3|=0,|y-1/2|=0x-3=0,y-1/2=0x=3,y=1/23x+2y=3×3+2×(1/2)=9+1=10
3x-y=2x-3y+5,移项3x-y-2x+3y-5=0x+2y=5x+2y-1=5-1=4
x=9-3/2y
x=2^(m+1)=2*2^m,2^m=x/2y=14+4^m=14+(2^m)^2=14+(x/2)^2=14+x^2/4
先去分母,得x-3y=2,所以y=x/3-2/3,x=3y+2
2X+3Y=53y=5-2xy=(5-2x)÷3x=(5-2x)/3
已知方程2x+3y=7,用含y的式子表示x是3y=7-2xy=(7-2x)÷3y=3分之(7-2x)
((X^2+Y^2)-(X-Y)^2+2Y(X-Y))/4Y=((X^2+Y^2)-(X^2-2XY+Y^2)+2Y(X-Y))/4Y=(X^2+Y^2-X^2+2XY-Y^2+2YX-2Y^2)/4
即(x²-4x+4)+|y-1/2|=0(x-2)²+|y-1/2|=0所以x-2=y-1/2=0x=2,y=1/2原式=(x²-y²)/xy÷(x+y)=(x
(x-2)^2=-|y-1/2|x=2,y=1/2x/y=4,y/x=1/4x+y=5/2(15/4)/(5/2)=3/2
3x-2y+1=02y=3x+1y=(3x+1)/2