10 (4x^3-9x^2 6x)的单调区间

等于37因为：【】都是一样的数字的话那他们就可以合并同类项：[]{10+1}*5=1980所以算出为37~

x^10+55*x^9+1320*x^8+18150*x^7+157773*x^6+902055*x^5+3416930*x^4+8409500*x^3+12753576*x^2+10628640*x

|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|

设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y

(x-3-1)/(x-3)-(x-5-1)/(x-5)=(x-7-1)/(x-7)-(x-9-1)/(x-9)1-1/(x-3)-1+1/(x-5)=1-1/(x-7)-1+1/(x-9)1/(x-7

 再问：额、不懂再答： 再答：后面的看做一个整体再问：好的吧、谢谢大神再答：回来的话，请采纳再问：啊、突然明白了呢。。。

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

X(1+2+3+4+5+6+7+8+9+10+11)=1980,X66=1980等于30

x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊

f(x)=1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+.1/(x+9)(x+10)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1

-2x>10x

x=5/7,x=15,x=8,x=6,x=1.1,x=2.1,x=2.5,x=5.

(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)=2（x-3)/(x-2)^2X(x+3)^2/(3-x)X(2-x)/(x+3)=2（x-

通分得[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),

∫2^x*3^x/(9^x-4^x)dx=∫(2/3)^xdx/[1-(4/9)^x]=[ln(2/3)]^(-1)∫d[(2/3)^x]/{1-[(2/3)^x]^2}={[ln(2/3)]^(-1

(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(

令s=X^2+X^3+……+X^9Xs=X^3+X^4+……+X^9+X^10Xs-s=X^10-X^2S=(X^10-X^2)/(X-1)所以原式=X-s+X^10=X+X^10-(X^10-X^2

(x-10+2)/(x-10)+(x-6+2)/(x-6)=(x-7+2)/(x-7)+(x-9+2)/(x-9)1+2/(x-10)+1+2/(x-6)=1+2/(x-7)+1+2/(x-9)1/(

(x+7)/(x-1)-(x+10)/(x+4)+(x+8)/(x+2)-(x+9)/(x+3)=[(x+10)-(x+7)]/[(x+1)(x+4)]+[(x+9)-(x+8)]/[(x+2)(x+

答：结论是无解的设1和4中间的正方形边长为x则左边中间的正方形边长为x+1左下角边长为x+1+x=2x+1所以：右下角正方形边长2x+1+x-4=3x-3所以：最大的正方形底部边长=2x+1+3x-3