把下列多项式因式分解 -4x^2 10x-搜答案-智慧作业帮

(a-b)+4(b-a)=(a-b)-4(a-b)=-3(a-b)

k为下列各数时,请将关于x的多项式x^2+kx+10因式分解（1）k=11x^2+11x+10=(x+1)(x+10)（2）k=-7x^2-7x+10=(x-2)(x-5)分解因式：a^2+3a+2=

(9a+b)(9b-a)(x+y-5)(x-y-5)

(1)(x+y)^2+4(x+y)+4=(x+y+2)^2(2)12a^3-12a^2+3ab^2=3a(4a^2-4a+b^2)(3)-x^2+6x-9=-(x^2-6x+9)=-(x-3)^2(4

3x²+21x+36=3(x²+7x+12)=3(x+3)(x+4)(x²-2x)²-11(x²-2x)+24=(x²-2x-3)(x

由此式(x+5)(x+n),得x=-5或x=-n.将-5代入x^2+mx+5=0得m=6.再将m=6代入原始式x^2+mx+5.可以因式分解得(x+5)(x+1）,得n=1

=(x+y)(x-y)-2x-4y-3=(x+y)(x-y)+(x-y)-3x-3y-3=(x-y)(x+y+1)-3(x+y+1)=(x-y-3)(x+y+1)

xy-x²=x(y-x)

-3a(1-x)-2b(x-1)+c(1-x)=(x-1)(3a-2b-c)

4x^2+4x-1=4x^2+4x+1-2=(2x+1)^2-2=(2x+1-√2)(2x+1+√2)

(x^2+1)^2-4x^2=(x^2+1+2x)(x^2+1-2x)=(x+1)^2(x-1)^2=(x+1)(x+1)(x-1)(x-1)

x^2-y^2-2x-4y-3=x^2-2x+1-y^2-4y-4=(x^2-2x+1)-(y^2+4y+4)=(x-1)^2-(y+2)^2=(x-1+y+2)(x-1-y-2)=(x+y+1)(x

x2+2xy+y2+4x+4y+4=（x+y）2+4（x+y）+4=（x+y+2）2．故答案为：（x+y+2）2．

x²y-4xy+4y=y(x^2-4x+4)=y(x-2)^2

（1）4x²-20xy+25y²=(2x)²-2*2x*5y+(5y)²=(2x-5y)²（2）9-12(x-y)+4(x-y)²=3

=(2x-3y)^2-4x^2=(2x-3y)^2-(2x)^2=(2x-3y+2x)(2x-3y-2x)=-3y(4x-3y)运用的是平方差公式

4x³y-9xy³=xy（4x²-9y²）=xy（2x+3y）（2x-3y）

x^4-18x²+81=(x^2-9)(x^2-9)=(x+3)^2*(x-3)^2

(1)x²+7x+1010=5×27=5+2∴原式=(x+5)(x+2)(2)x²-2x-8-8=(-4)×2-2=-4+2∴原式=(x-4)(x+2)(3)y²-7y+