把多项式2x∧4-3x³y-x³+y²写成两个二项式的差,使被减式中不含字母y
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/08 12:20:10
3x^2y-3xy^2+y^3-x^3=y³-3xy²+3x²y-x³
原式=(x²-4y²)+x-2y=(x+2y)(x-2y)+(x-2y)=(x-2y)(x+2y+1)
1,(x-y)³-(x-y)²(x+y)=(x-y)²(x-y-x-y)=-2y(x-y)²2,x(x²-xy)-(4x²-4xy)=x
=(x+y)(x-y)-2x-4y-3=(x+y)(x-y)+(x-y)-3x-3y-3=(x-y)(x+y+1)-3(x+y+1)=(x-y-3)(x+y+1)
-1/2y^4-5x^2y^3+x^3y^2+2x^4y+1
3m(x-y)^2-9n(y-x)^3=3(x-y)^2(m-3n(y-x))=3(x-y)^2*(m+3nx-3ny)另一个多项式为:m+3nx-3ny
差是:(3x+2y)-(4x-2y)=3x+2y-4x+2y=-x+4y
-2x²-2x+xy+y²
x^2-y^2-2x-4y-3=x^2-2x+1-y^2-4y-4=(x^2-2x+1)-(y^2+4y+4)=(x-1)^2-(y+2)^2=(x-1+y+2)(x-1-y-2)=(x+y+1)(x
(3x-2y)-(4x-2y)=3x-2y-4x+2y=-x
4x^2-3xy-2+5y^2=(4x^2-2)-(3xy-5y^2)
x的降幕3x(4)y-3x(3)y(2)+2x(2)y(4)-y(3)xy的升幕3x(4)y-3x(3)y(2)-y(3)x+2x(2)y(4)
/>(1)原式=(x+2y)(x-2y)+x-2y=(x-2y)(x+2y+1)第二题狮子看不清,能在描述一遍吗再问:分解因式:(x²+1)²-x²+x(x-2)(x
3x-2y-(4x-2y)=3x-2y-4x+2y=-x
由题意得:差=3x+2y-(4x-2y),=-x+4y.故填:-x+4y.
x^3+4x^2y-3xy-y^3
x²-y²-2x-4y-3=(x+y)(x-y)-2x-4y-3=(x+y+1)(x-y-3)(十字相乘)十字相乘x+y1×x-y﹣3x^2y+y^2x=96xy(x+y)=96x
因为,多项式2x^4-3x^2y-x^3+y^2中不含字母y的单项式为2x^4和x^3;所以,把多项式写成两个二项式的差,使被减式中不含字母y,结果如下:2x^4-3x^2y-x^3+y^2=(y^2
用提取公因式法,提取(x+3y)原式=(x+3y)[(3x-4y)-(x-2y)]=(x+3y)(2x-2y)=2(x+3y)(x-y)