把方程组2x-y=2 3m
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1题:3x+2y=m+12x+y=m-12(2x+y)=2m-2所以,(4x+2y)-(3x+2y)=2m-2-(m+1)解得:x=m-3;y=5-m;当m为何值时,x>y,m-3>5-m解得:m>4
1.2x+3y-4=02x+3y=43y=4-2xy=4/3-2x/3y=-2x/3+4/3所以k=-2/3m=4/35%x+53%y=25%x300所以5x+53y=75005x+5y=15002式
2X+3Y=15M,5X-3Y=-M两式相加7X=14MX=2MY=11/3M
3x+2y=m+12x+y=m-1x=m-3y=5-mx>ym-3>5-mm>4所以,当m>4时x>y
3x+2y=m+1①2x+y=m-1②,由②×2-①得,x=m-3;把x=m-3代入②得,y=-m+5,∵x>y,∴m-3>-m+5,解得m>4,∴m的最小整数值是5.
(1)x=-y代入方程组-3y+2y=m+1.①-4y+2y=m-1.②①*2-②得m=-3(2)y+1=x代入方程3(y+1)+2y=m+1.③4(y+1)+2y=m-1.④③*6-④*5得m=-1
x=7,y=-2.三个方程求解,一二方程消去m,得到2x+7y=0.2x+7y=03x+2y=17二元一次方程组.
2x+y=1+3m(1)x+2y=1-m(2)(1)+(2)得:3x+3y=2+2m所以:x+y=(2+2m)/3因为x+y〈0则:(2+2m)/3
将y=x+m代入下式得:x^2+2(x+m)^2=1x^2+2(x^2+2xm+m^2)=1x^2+2x^2+4xm+2m^2=13x^2+4xm+2m^2-1=03x^2+4xm+m^2+m^2-1
1式乘以9得9x+18y=45m2式乘以5得5x-10y=45m上面两式想减得,4x+28y=0x=-7y再结合3x+2y=19得到x=7y=-1再把x=7,y=-1代入1式得m=1
解方程组3x+2y=m+12x+y=m-1得:x=m-3y=5-m因为:x>y所以,m-3>5-m2m>8m>4当m>4时,x>y
2X+Y=1-MX+2Y=2两式相加3x+3y=1-m+2=>3(x+y)=3-mx+y>03-m>0m
2x+5y=15m.(1)5x-3y=-m.(2)由(1)*5-(2)*2得31y=77m所以y=77m/31再代入(2)式得x=40m/31
x的值比y的值小5y-x=5x-y=-5x-y=9m=-5m=-5/9x+2y=3m(1)x-y=9m(2)(1)*5+(2)*45(x+2y)+4(x-y)=5*3m+4*9m9x+6y=51m3x
两方程相加,得x+y=1-m/3因为x+y
方程组解答要靠“消元”的方法.在3x+2y=m+12x+y=1+3m4x+3y=m-1x+2y=1-m中,要求x和y的值,就把m消掉就可以.由3x+2y=m+1得m=3x+2y-1代入2x+y=1+3
如果x,y符号相反,绝对值相等,即y=-x,代入原方程组,得3x-2x=m+1,4x-2x=m-1,即x=m+1,2x=m-1解之,2(m+1)=m-1,得m=-3如果x比y大1,即x=y+1,代入原
x=2-2y2(2-2y)+y=1-m4-4y+y=1-m3y=3+my=1+m/3x=2-2(1+3/m)x=-2m/3做完了才发现没分问题简单也多少给点嘛呵呵
解方程X=(6+M)/3Y=2M/3-2因为x>0y-6m
1、消元求y=(5m-28)/5,x=(10m+29)/5;根据题意:(5m-28)/5>=0,得:m>=28/5,(10m+29)/5>=0,得:m>=-2.9;所以,m的取值范围为:m>=28/5