10(x^2 y^2)-16xy-16=0
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原式=(x-y)²-10(x-y)+16=(x-y-2)(x-y-8)原式=(2x-y)(x+2y)-x+8y-62x-y3×x+2y-2原式=(2x-y+3)(x+2y-2)
3xy是3x原式=(x-3y)(x+2y)+3x+y+2十字相乘x-3y2×x+2y1所以原式=(x-3y+2)(x+2y+1)
[(xy+2)(xy-2)-2x2y2+4]÷(xy)=(x2y2-4-2x2y2+4)÷xy=-x2y2÷xy=-xy,当x=10,y=1/25时,原式=-2/5.
[(xy+2)(xy-2)-2x^2y^2+4]/(xy)=[(x^2y^2-4)-2x^2y^2+4]/(xy)=-x^2y^2/xy=-xy=-10*(-1/25)=2/5
对.前提是x不等于y
(x+y-2xy)(x+y-2)+(1-xy)^2=(x+y)^2-2(1+xy)(x+y)+4xy+1-2xy+x^2y^2=(x+y)^2-2(1+xy)(x+y)+(1+xy)^2=(x+y)^
x^+2xy+y^+4=16(x+y)²=16-4=12(1)x^-2xy+y^=16(x-y)²=16(2)(1)-(2)2y*2x=-4xy=-1(3xy+6y^)+|x^-(
=xy(x-y)×[-xy/(x-y)]=-(xy)²=-x²y²
【x²+xy/(x-y)】/【xy/(x-y)】=【x²(x-y)/(x-y)+xy/(x-y)】/【xy/(x-y)】={【x²(x-y)+xy】/(x-y)}/【xy
1、已知2x²+xy=10,3y²+2xy=6,求4x²+8xy+9y²的值为?分析:通过观察,可以把8xy拆成2xy+6xy,分别于剩余的两项组合,并提取公因
x^2-10x-11=(x-10)(x+1)x^2y^2-16xy+60=(xy-10)(xy-6)(x+y)^2-7(x+y)-18=(x+y-9)(x+y+2)x^2-13xy-30y^2=(x-
双十字相乘.
(xy-y^2)÷x-y/xy=y(x-y)×[xy/(x-y)]=xy²
原式=(x+2y)(2x-3y)-x-16y-10十字相乘x+2y2×2x-3y-5x和y系数都符合所以原式=(x+2y+2)(2x-3y-5)
2x^2+xy-6y^2-x-16y-10=(x+2y)(2x-3y)-5(x+2y)+2(2x-3y)-10=(x+2y)[(2x-3y)-5]+2[(2x-3y)-5]=(x+2y+2)(2x-3
(x+y)(x-y)-x(y+1)-y(y+1)=(x+y)(x-y)-(x+y)(y+1)=(x+y)(x-2y-1)
(x-y)/x²÷(x²-2xy+y²)/xy×(xy-x²)=(x-y)/x²÷(x+y)²/xy×x(y-x)=(x-y)²/
原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-
利用公式法逆向因式分解(x+y)(x^2-xy+y^2)=x^3+y^3(x-y)(x^2+xy+y^3)=x^3-y^3都是公式可以自己乘开来试下可以抵消的(x^2-xy+y^2)和(x^2+xy+