c 编写函数,计算任意两个整数的和,在主函数中调用该函数并输出结果,从键盘输入这

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

#includelongfactorial(intm,intn){longsum=1,sum1=1;inti;if(m-n>n){for(i=m;i>m-n;i--)sum*=i;for

#includemain(){inta,c,b,d;scanf("%d%d",a,b);c=a+b;d=a*b;printf("%d%d",c,d);}再问：采用函数的方法再答：先输入两个数，然后执行

#includeintfun(intn){ints=0;while(n){s+=n%10;n=n/10;}returns;}main(){intn;scanf("%d",&n);printf("%d\

#include<stdio.h>int getmax(int a,int b){      re

#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}voidmain(

#include<stdio.h>double zc(double x, double y){    ret

楼主你好,这是源程序,是用辗转相除法写的#includeintmax(intp_a,intp_b){\x09if(p_b==0)\x09\x09returnp_a;\x09else\x09\x09re

Reverse

intfunction(intx)//x为输入的整数{inta,b=0;if(x>0)a=x;elsea=-x;while(a%10!=0){b+=a%10;a=a/10;}returnb;}

/*36/736/7=5.1428612^212^2=1446+96+9=158-78-7=1qDownPressanykeytocontinue*/#include <stdio.h

#includeintmain(){intx,y,a;scanf("%d",&x);scanf("%d",&y);a=x*y;printf("Theaverageis%d\n",a);return0;

这个很简单的//编写一个函数,计算100以内个位数是5且被3整除的整数个数#include"stdio.h"voidmain(){intjishu(intn);intcount=0;intn=0;pr

关于你说的变量的声明（定义）问题,你需要掌握变量的作用域的概念：我给你一个例子,看看能否了解.

源码如下：#includeintsum(inta,intb){\x09returna+b;\x09}intmain(){\x09intm=1,n=2,k=3;\x09intt=sum(sum(m,n)

#includeusingnamespacestd;voidmain(){inta=0,b=0;cin>>a>>b;cout

#includedoubleDistance(V&v1,V&v2){dx=v1.x-v2.x;dy=v1.y-v2.y;dz=v1.z-v2.z;returnsqrt(x*x+y*y+z*z);}其中

#includevoidmain(){inta,b,sum=0;printf("请输入两个整数：");//将两个改成n个就好了scanf("%d%d",&a,&b);sum=a+b;printf("%

intfun(inta,intb){if((a/10)=10||(b/10)=10){std::cout

完整程序如下：#includefun(intx,inty){intr;if(x>y){x=x;y=y;}r=x;x=y;y=r;r=x%y;while(r!=0){x=y;y=r;r=x%y;}ret