提示用户输入圆的半径,计算圆的周长和面积C#

#include <stdio.h>#include <math.h>//输入三个点void inputThreePoint(double&nbs

CLEARSETTALKOFFINPUT"请输入半径:"TORL=2*PI()*RS=PI()*R*R"半径为R的圆的周长为:",L"半径为R的圆的面积为:",SSETTALKON

#definePI3.1416//后面不需要;#include"stdio.h"//注意关键字之间要有空格intmain(){floatr,s,c;scanf("%f",&r);c=2*PI*

#include#definePI3.1415926\x05\x05voidmain()\x05{\x05doubler,s;scanf("%f",&r);s=PI*r*r;\x05printf("A

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespaceConsoleApplic

算法一：#includemain(){intn1,n2,gcd=1,k=2;scanf("%d%d",&n1,&n2);while(k0;i--)if(n1%i==0&&n2%i==0)printf(

结构体可以,楼上的说了.如果没学结构体可以用二维数组,floata[3][2].第一维是第一个顶点第二个顶点第三个顶点.通过两层for循环进行数据输入,外层控制顶点次序,内层控制每个顶点的横左边和纵坐

PublicSubcommand1_click()dimrasintegerr=val(inputbox("请输入半径"))s=3.1415926*r^2msgbox"圆的面积为:"&sendsu

publicclassFactorial{publicstaticvoidmain(String[]args){if(args.length!=1){System.out.println("请输入n值

要求用什么语言啊?求简单写个在matlab上跑的：r=input('r=?');D=2*pi*rS=pi*r*r再问：c语言呀哥哥再答：#include#includemain(){floatpi=3

#includevoidmain(){floatr,d,Cs;cout

亲,这个是源码using System;using System.Collections.Generic;using System.Linq;using Sys

PrivateSubCommand1_Click()DimbjAsSingleDimzzAsSingleDimmjAsSinglebj=CSng(Text1.Text)Ifbj

if(flag==0){\x05intiLast,iNext;\x05iLast=sqrt(nums);\x05iNext=iLast+1;\x05printf("itisnotaperfectsqu

#include#definepai3.15149256voidmain(){doubler,c,s;printf("pleaseinputr\n")scanf("%lf",&r);printf("c

#include#include//因为用到了sqrt()函数,sqrt()为开根号usingnamespacestd;intmain(){cout

他们的答案好像都没有输出结果.Dim r, s, c As IntegerPrivate Sub Command1_Click()

constpi=3.1416subcircle（byvalrassingle,Lassingle,aassingle,VASSINGLE）L=2*pi*rA=pi*r*rV=4/3*r*r*r*pie

#includeclasscircle{private:intr;public:voidinput(){cout

#includemain(){doublea,b,z,c;cin>>a>>b;//输入长和宽z=a*b;//计算面积c=2*(a+b);//计算周长cout