数组存储并输出Fibonacci数列的前20项,按5个一行输出,

voidmain(){intm[3][3];inti,j;for(i=0;i{for(j=0;j{printf("请输入第%d行第%d列的数：",i+1,j+1);scanf("%d",&m[i][j

#includeintmain(){floata[10],min,max;inti;printf("pleaseenter10num\n");for(i=0;i

修改如下：#include"stdio.h"intmain(){ints[40],i=0,j,num=0,a=0,b=0,c=0;for(i=0;i

#includeintmain(){intarray[5]={2,1,0,3,5};inti,min,max;min=array[0];max=array[0];for(i=0;iarray[i])m

/*Matrix_main.cpp*///#include#include#include#include/*#include*/voidmain(void){intcol,row,row_s;/*t

main也是函数,括号里是他的参数voidmain(intargc,char*argv[])假设程序编译成为cp.exe然后在命令行中输入c:\>cp.exedoc1.txtdoc2.txt这行中有三

#includevoidmain(){inti,sum=0;inta[]={1,2,3,4,5};for(i=0;i

int[]a=new[]{4,7,6,9,3,1,5,8,0};Listb=newList(a);b.Sort(delegate(intx,inty){return(y-x);});最大值：b[0]最

#include<stdio.h>int main(){int i,a[20]={1,1};printf("%d %d ",

可用递归算法实现N重循环来实现详细请QQ:115499275以下也许有助于你以下为文件的内容:VERSION5.00BeginVB.FormForm1Caption="Form1"ClientHeig

#includeintmain(){inta[100];//定义a来存放数组inti,n,k=0,f;printf("请输入数组的个数：");scanf("%d",&n);printf("请输入数组的

#include"stdio.h"voidmain(){\x09inta[10];\x09inti;\x09intmax,min;\x09for(i=0;i

数组为a=[002.936.069.1912.11215.11518.21821.32124.32427.327……]你的数据那么b=diff(a)就是后一个数减前一个数的差plot(b)画差值的图再

#includevoidmain(){inta[10]={1,2,3,4,5,6,7,8,9,10};intb[6]={2,3,4,5,6,7};intc[10],i,j,k=0,n;for(i=0;

#includevoidmain(){\x05introw,column,max,min,i,j;\x05intaverage=0;//数组初始化inta[5][5]={{1,2,3,4,5},{6,

#includevoidmain(){inta[100];inti,min;printf("输入100个数\n");for(i=0;i

所要求的程序已经完成,#include<stdio.h>#include<stdlib.h>main(){ inta[100],i,s=0; randomi

main(){inta[10],i,sum=0,x=0;/*初始化数值*/for(i=0;i

#includevoidmain(){inta[10]={2,3,5,1,8,4,7,9,0,6};inti,s;intmax,min;max=min=a[0];for(i=s=0;imax)max=

#includeintmain(){doubled[10],sum=0,ave=0;inti;for(i=0;i