方程2x²-6x-1=0

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解方程(x-1)(x+2)(x+3)(x+6)+20=0

(X2+5X+6)(X2+5X-6)+20=0(X2+5X)2-36+20=0(X2+5X)=16X2+5X-4=0或X2+5X+4=0X=-5+(-)根号(41)/2或X=-1X=-4

解方程(2x+1)(3x-2)-6(x+1)(x-1)=0

(2x+1)(3x-2)-6(x+1)(x-1)=06x^2-4x+3x-2-6(x^2-1)=06x^2-x-2-6x^2+6=0-x+4=0x=4再问:为什么我做的最后对于3/7再答:你怎么做的呀

解方程;2x平方+6x-1=0

由求根公式得:x=[-6±√(6²-4*2*(-1)]/(2*2)=(-3±√11)/2

解方程①(x+3/x-1)²-5(x+3/x-1)+6=0 ②x²-2/x+3-6x+18/x

1,(1)将(x+3/x-1)设为a(2)得a²-5a+6=0(3)因式分解(a-2)(a-3)=0(4)a1=2a2=32,化简得x³-4x²+18=0

解方程(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)

(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)x^3+x^2+x-6x^2-6x-6-x^3+x=2x-5x^2-4x-6=2x6x=-6x=-1

(6/x-2)=(x/x+3)-1解方程

两边乘(x+3)(x-2)6x+18=x²-2x-x²-x+66x+18=-3x+69x=-12x=-4/3经检验,x=-4/3是方程的解

解方程:(4/x-2)+(x-1/x-5x+6)+(2/3-x)=0

4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)谁会解这道方程题

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/

解方程(x+1/x+2)-(x+2/x+3)=(x+5/x+6)-(x+6/x+7)

我给个思路吧(X+2-1/X+2)-(X+3-1/X+3)=(X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决

分式方程.x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)

(x-9)/(x-7)-(x+1)/(x-1)=(x-8)/(x-6)-x/(x-2)[(x-9)(x-1)-(x+1)(x-7)]/[(x-7)(x-1)]=[(x-8)(x-2)-x(x-6)]/

解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)

2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99

解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

x/(x-2)+(x+9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)怎样解这道方程

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/

解方程:x+2/x+1-x+3/x+2=x+6/x+5-x+7/x+6

通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2

解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(

方程(x+1)(x+2)(x+3)(x+4)(x+5)(x+6)(x+7)(x^2+8x+9)+64=0

1,应该是x是几次幂就有几个根吧,所以应该是7+2=9个2.-7.036622145,-6.489288572,-6.200988153,-4.734373320,-4.289168546,-2.77

x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程

你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你

解方程:x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/

x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程

X-1/X-2-(X-2)/(X-3)=(X-5)/(X-6)-(X-6)/(X-7)(X-1)(X-3)-(X-2)²/(X-2)(x-3)=(X-5)(X-7)-(X-6)²/

几道初一数学题(x^2-1)/(x-3x) +( x-1)/(2x-1)=0 解方程已知方程 x分之3 + x-1分之6

(1)原方程即为:(x2-1)/(-2x)+(x+1)/(2x-1)=0即为:(x2-1)/(2x)=(x+1)/(2x-1)即:(x+1)(x-1)(2x-1)=(2x)(x+1)双方除以(x+1)