C语言中任意输入一个整数(小于10位),求它的位数

#includevoidmain(){inti,n,z,f,x;printf("请输入一共要处理几个数：");scanf("%d",&n);for(i=z=f=0;i0)z++;elseif(x

#includevoidsx(intx[],intn){inti,j,t;for(i=0;i

你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs

#include　　voidmain(){inti;intj[6];inta;intsum=0;for(i=0;i

一：#includevoidmain(){inti,j;inta[5][3];for(i=0;i

可以用sprintf(str,"%d",num);将数字输出为字符串,再用strlen(str)检查其长度：intnulen(intnum){charstr[10];sprintf(str,"%d",

#includeintmain(void){intn,m,j=0,k=0;printf("请输入一个数;\n");scanf("%d",&n);for(;n>0;){m=n%10;if(m%2==0)

printf("输入一个小于1000的整数x",x)；x不需要,改成printf("输入一个小于1000的整数:")；printf("输入的数据不符合要求,重新输入一个小于1000的整数x",x)同理

#include#includeintmain(void){intn,sum=0,count=0,s;printf("输入一个整数:");scanf("%d",&n);while(n){s

#includevoidmain(){inti,j,m,n=0,a[100],*xx=a;scanf("%d",&m);for(i=2;i

main(){intx;scanf("%d",&x);x=(x%10)*100+(x/10%10)*10+(x/100)printf("%d\n",x);}

请输入:100357111317192329313741434753596167717379838997Pressanykeytocontinue#include#includeintmain(){\

请输入:100357111317192329313741434753596167717379838997Pressanykeytocontinue#include#includeintmain(){

方法一：//用数学函数#include#includevoidmain(){inta;scanf("%d",&a);printf("%d\n",abs(a));}方法二：//判断#includevoi

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){\x05intn,sum=0;printf("Typeaninte

#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%5==0)c=1;if(a%7==0)d=1;elseif(c==1&&d==1)p

#includeintStrchr(chars[],charch){intl,i;intj=0;l=strlen(s);for(i=0;i

#include<stdio.h>#include<math.h>int main(){   int x,y; &n

IconfessthatI'mansweringfortask.#includeintmain(){intn,m=1,i=1;scanf("%d",&n);if(n{printf("error\n")

#include#includevoidmain(){\x09intn,i;\x09scanf("%d",&n);\x09if(n==1)\x09{\x09\x09printf("1isnothing