C语言如何输入一个数组并计算其总和

#include#defineCOUNT100main(){inta[COUNT],i,x,no=0;for(i=0;i

#includeintmain(){inta,sum=0;scanf("%d",&a);while(a){sum+=a%10;a/=10;}printf("sum=%d\n",sum);return0

#includeintmain(){intnum=0;ints=0;inti=0;scanf("%d",&num);while(num){s+=num%10;num=num/10;i++;}print

/*Matrix_main.cpp*///#include#include#include#include/*#include*/voidmain(void){intcol,row,row_s;/*t

已经运行确认了：#includemain(){intavg,i,sum=0,a[11];printf("请输入十个整数\n");for(i=1;i

#includevoidmain(){inti=0,sum=0,a[100];for(i=0;i

#include <stdio.h>#include <stdlib.h>#define size 5int main(){&

代码：#include <stdio.h>int sum(int n){\x05int s = 0;\x05while(n>

#include"stdio.h"intmain(){inta,i,sum=0;printf("请输入3位的整数\n");scanf("%d",&a);for(i=0;i

intfunc(int*a;intb)//这里a表示数组名,b表示数组的元素个数{intc=0;inti;for(i=0;i

#includeintmain(){inti;intj;intk;inta[4][4];for(i=0,k=1;i{intsumrow=0;for(j=0;j{a[i][

#includevoidmain(){inta;printf("请输入一个三位数：");scanf("%d",&a);printf("各位数上的乘积为：%d\n",(a/100)*(a%10)*(a/

#includeintmain(void){inta[3][4],i=0,j=0;for(i=0;ifor(j=0;jscanf("%d;",&(a[i][j]));for(i=0;iprintf("

#include#include#defineE2.7182voidmain(void){floatx;floaty;scanf("%d",&x);if(x>=-1)y=pow(x,2)+1;

#include#include#definePI3.14159intmain(void){floatr,h,V=0;printf("Pleaseinputr=h=\n");loop:scanf("%

1.编译不通过数组定义时,不能使用变量,即使变量已赋值,所以inta[n]；是错的解决方法,你可以直接定义一个大的数组,比如inta[100],然后再用n限制输入的个数2.数组下标是从0~n-1,所以

#includevoidmain(){\x09intyear;\x09printf("请输入年份：");\x09scanf("%d",&year);\x09if((year%4==0&&year/10

问题在注释里指出来了,看下面代码：#include<stdio.h>#define N 5void Input(int str[N][N])//指明

#includeintmain(){inti,s,t,a[100]={0};t=0;s=0;for(i=0;i

main(){inta[10],i,sum=0,x=0;/*初始化数值*/for(i=0;i