C语言怎么让随机产生的大写字母或数字的概率相同

#include#include#includeusingnamespacestd;intmain(){intha=0;inthb=0;intn;cin>>n;srand((int)time(0));

#include#include#include#includeintmain(){\x05\x05charr[7];\x05inti,j,k,t,f;\x05srand(time(0));\x05f

#include#include#include#defineN10//随机出10道题目intmain(){\x09intnum1,num2,num3,count=0,result,resultTru

思路：分别产生个、十、百位上的随机数,依次组合在一起#include#include#includeintmain(){inti,tmp;num=0;srand((unsigned)time(NULL

#include#include#include#includevoidsushu(int*a);intmain(){inta[50],i;intt=200,d=500;srand(time(NULL

chars(void){if(rand()%2)returnrand()%26+'a';elsereturnrand()%26+'A';}想生成多少个,就调用多少次这个函数

#include#include#include#include#include"windows.h"boolisprimer(intn){inti,sr=(int)sqrt(n)+1;for(i=2

20-90共有71个数字x=rand()%71+20;rand()%71产生0-70的随机数字

#include <stdio.h>#include <stdlib.h>#include <time.h>int mks(

#include#include#include#defineN1000intfun(inta[],intnum);voidmain(){inti,a[N],b,num,n;printf("\n请输入

就是这个!刚刚出了点小错,现在可以了……楼主要解释可以追问#include#include#includemain(){charc;srand(time(0));c=rand()%3+65;print

#include#include#includeintmain(){inta,b,c;srand((unsigned)time(0));a=rand()%100+1;b=rand()%100+1;c=

dima(9)a(0)=25a(1)=33`````a(9)=99i=int(rnd*10)?a(i)看明白了吗?有问题再HI我再问：输出的三个数要求不重复的呢，你这样的只有一个

//小学生四则运算#include#include#include//产生[a,b]区间的随机数#defineRANDOM(a,b)(rand()%((b+1)-(a))+(a))//产生1-20的整

产生100为模的两个数字,记录下来；生成一个以4为模的数字,1对应+,2对应-.计算.#include<stdio.h>#include <time.h>void&n

您这代码b=rand()%((int)(100/b))+1;有问题,b不能被产生出来,因为b根本还没确定是多少,就被用去100/b了下面的代码可以产生两个能整除的数：#include#includem

#include#include#includeintmain(){inti,randomnum,yourguess;randomize();randomnum=random(101);printf(

#include"stdio.h"#include"stdlib.h"#definerandom(x)(rand()%x)voidmain(){for(inti=0;i

//---------------------------------------------------------------------------#include<stdio.h>

用srand和rand函数：举例：#include#include#includeintmain(){inta[10][2];inti,j,x,y;srand(time(NULL));/*随机数种子*