C语言用函数5*5矩阵的对角线之和
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 08:23:37
#defineN10;main(){inti,j;inta[N][N];intsum=0;for(i=0;i
#includemain(){\x09inta[3][3],i,j,sum=0;\x09printf("请输入数组元素:(3*3)\n");\x09for(i=0;i
for(i=0;i=0;i--,j++)sum1=sum1+a[i][j];
#includevoidmain(){inta[3][3];inti,j;intsum=0;intsum1=0;//inputfor(i=0;i
#includemain(){inti,j,sum=0,n=0;inta[3][3];//创建矩阵printf("请输入要计算的矩阵:\n");for(i=0;i
#includeintmain(){\x05inta[5][5]={{1,2,3,4,5},{1,2,3,4,5},{5,4,3,2,1},{1,3,4,2,5},{5,4,3,2,1}};\x05i
#include"stdio.h"voidmain(){intmagic[5][5]={{17,24,1,8,15},{23,5,7,14,16},{4,6,13,20,22},{10,12,19,
#includevoidmain(){inta[3][3];inti,sum1,sum2;for(i=0;i
#include"stdio.h"intmain(){inta[10][10]={0};intn,i,j,sum1=0,sum2=0;scanf("%d",&n);for(i=0;i
for(sum=0,i=0;i
#include<stdio.h>main(){\x05inta[100][100],i,j,n,A=1,B=1;\x05chart;\x05scanf("%d\n",
先收藏,等一会在弄.#include#includeintmain(){inti,j,m=0,a[3][3];printf("请输入9个整数\n");for(i=0;i再问:好的,先谢了
matrix_mul(int**A,int**B,int**C,intm,intp,intn){for(inti=0;i{for(intj=0;j{C[i][j]=0;for(intk=0;k{C[i
inta[5][5],可以拆开来写就比较容易理解int*a[5];//宣告了五个int的指针inta0[5],a1[5],a2[5],a3[5],a4[5];//宣告了五个数组,每数组含5个inta[
#includeintmain(){intarray[3][3],sum;inti,j;for(i=0;i{for(j=0;j{scanf("%d",&array[i][j]);}}sum=array
#include"stdio.h"intmain(){intshuzu[4][4];inti;intj;intmaxs;intsum=0;for(i=0;i
#includeintmain(){floatst[3][3],sum=0;inti,j;for(i=0;ist[i][j];for(i=0;i
for(i=1;i
#includevoidmain(){inti,j;inttemp,res1=0,res2=0;for(i=0;i
//zd_40.cpp:Definestheentrypointfortheconsoleapplication.//#includeintmain(intargc,char*argv[]){inti