C语言程序计算ax^2 bx c
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/02 17:37:41
#include"stdio.h"voidfun(intn,intk){intj;doublesum=0;for(j=1;j
应该这样写:#include#includevoidmain(){inti,n,sum;sum=0;i=2;for(n=1;n
#includeintmain(){inti;doublesum=0.0;doublejiecheng(doublenumber);for(i=1.0;i
没得错误,main函数前面加void就好了
#includeintmain(){inti,j,sum,result=0;for(i=1;i
intfun(intn){//在该函数体中求1~n的累加值//用return语句返回累加值intsum=0;inti;for(i=1;i
#includemain(){doublex,y;scanf("%lf",&x);if(x
这个东西关键是递归算法的确定,需要一点数学知识.#include//递归计算函数intcalc(intx){if(xif(x==1){return1;}elseif(x==2){return3;}el
1+2+3+...100inti,s;for(i=1;i
#include#includeintmain(){intsum=0;intindex=0;for(index=1;index
#include#includevoidmain(){doublecoe[20],x,sum=0;inti,n;printf("请输入总项数:");scanf("%d",&n);printf("请按指
usingSystem;usingSystem.Collections.Generic;usingSystem.Text;usingSystem.Collections;namespacecacFC{
#include"stdio.h"voidmain(){inta[100],i;intcnt=0;for(i=0;i=-26&&a[i]
这个答案一眼就可以看出是-50,(1-2)+(3-4)+……(99-100)这样就是50个-1,非要用一个个计算,见下面代码:#include<stdio.h>main(){int&nbs
#include <stdio.h>int main(){ float x, tax = 0;
#include#include
你先把公式告诉我,我帮你写
运用了加法交换定律乘法交换律乘法分配律
#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i
#includeintmain(){inti,s=0;for(i=1;i