C语言编写程序计算1! 2! 3! 4! -- 10!并输出结果-搜答案-智慧作业帮

#includeintmain(){inti,j,sum,result=0;for(i=1;i

//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV

intfun(intn){//在该函数体中求1～n的累加值//用return语句返回累加值intsum=0;inti;for(i=1;i

#include "stdio.h"int main(){ float i,s,t; &nbs

#includemain(){doublex,y;scanf("%lf",&x);if(x

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inti,j,k,sum;for(sum=1,i=0;i

longadd(intn){intt=n-1;if(t>1){longresult=n*t;longsum=result+add(t);returnsum;}else{returnn;}}楼上的方法,

#include#includeintmain(){intsum=0;intindex=0;for(index=1;index

TCHARszBuff=newTCHAR[10000];这里把所有的内容放到szBuff里intaverage,iWordNum,iLine;while(*szBuff++!='\0'){if(*sz

#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i

#includemain(){floatsum=0.0;inti,n;floata=-1.0;printf("sum1-1/2+1/3.");scanf("%d",&n);for(i=1;i

#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fact(n-1);}intmain(){printf("5!+10!=%d\n"

inti,s=0,flag=1for(i=1;i

#include <stdio.h>int main(){ float x, tax = 0;

main(){inta;intsum=0;foreach(a=1;a

因为3个加法的运算规律是相同的,使用一个函数来计算循环值#includeintfun(intn)//计算累加结果函数{//这里还可以判断下n是否小于等于0intsum=0;inti;for(i=1;i

main(){inta,b,c;c=a+b;scanf("%d%d",&a,&b);printf("%d",c);}

#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i

#includeintmain(){inti,s=0;for(i=1;i

m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.