c语言计算1! 2! 3! ...9!-搜答案-智慧作业帮

intmain(){intret=9*8*7*6*5*4*3*2;printf("resultis%d\r\n",ret)}或者intmain(){intret=1;for(i=2;i

if(i=100)//这里改成100==ibreak;

、注意,数据别溢出.long是4个字节,double是8个字节.（Windows,VC6.0).2、你的程序：printf("1!+2!+.+20!=%ld\n",t);,最后也应该输出s.但是结果也

#include"stdio.h"intmain(){ doublesum=0; &

#include<stdio.h>void main(){ double e,sum=0; &nbs

你自己写点,有问题我帮你调试.这个不难再问：不会写啊再答：编程就是个熟练活儿，多练习就会了# include <stdio.h>int main(void){

/*用C语言编程:计算满足条件1^3+2^3+3^3+…

#includevoidmain(){inti,b=1,s=0;for(i=1;i

#include "stdio.h"double fun(int n)//用double提高精度和计数位数.{ double&n

#includevoidmain(){longt=1,s=0;intn;for(n=1;n

#includemain(){ints=0,n=1,a;a=2n-1;while(a

#includemin(){intsum=0,i;for(i=1;i

#include"stdio.h"main(){inti,p=1,sum=0;for(i=1;i<=10;i++){p=p*i;sum=sum+p;}printf("%d\n",sum);}运行

每次从到for(t=1,s=0,i=1;t

#include"stdio.h"main(){double x,y=0;int m,n;for(n=1;n<=10;n++) { x

ints=0;for(inti=1;i

#includevoidmain(){intn;doubles=0,t=1;for(n=1;n

#include#includeintmain(){inti,m,t,k;doubles;s=0;m=1;for(i=1,k=1;i

#includeintfun(intn){inti,sum=0,f=1;for(i=1;i

#includeintmain(){longjiechen(intn);FILE*p;inti;longsum=0;for(i=1;i=1;i--)sum=sum*i;returnsum;}