每行输出5个
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#include"stdio.h"voidmain(){inta[20],i;a[0]=a[1]=1;for(i=2;i
# include <stdio.h>int main(){int a = 0,b = 0,c
筛法求素数,速度超快.public class SievePrime {\x09\x09static int maxNumber =&nbs
//这样就ok了,刚写的code,测试通过,如果有疑问,欢迎交流#include<iostream>using namespace std;int main(
#include#include#includeintmain(){inta[15],i,j;srand(time(NULL));for(i=0;i<15;i++)a[i]=rand()%100;fo
PrivateSubCommand1_Click()dimi,a(),basintegerfori=21to1000ifimod21=0thenb=b+1redimpreservea(b)a(b)=i
//输出101~115之间不能被3整除的数,每行输出5个.要求使用continue语句#includevoidmain(){\x09inti;\x09intcount=0;\x09for(i=101;
#include#includevoidmain(){intn;printf("pleaseinputn:");scanf("%d",&n);inti,j,sum;for(i=1;i
上面两位的复杂度有点高.简单点做法,把100以内的2,3,5,7的倍数(除2之外)去掉,就是所有质数啦#include#includeusingnamespacestd;intmain(){inti,
#include"stdio.h"#include"math.h"voidmain(){inti,j,a,k;k=0;for(i=100;i
#includemain(){inta[10];inti;for(i=0;i
#include#include#includeusingnamespacestd;boolisPrime(intm);intmain(){intcount=0;for(inti=100;i再问:LI
#include"stdio.h"voidmain(void){inti=0,count=0;do{if((i%3==0)&&(i%5==0))//同时被3和5整除{printf("%d",i);co
#include "stdio.h"int isPrime(int n){ int i; &nb
#includeintmain(){inti1,i2,i3,i4,i5,i6,i7;intv[31];intx[8];inti,j,flag,k=0;FILE*fout;fout=fopen("abc
PrivateSubCommand1_Click()DimiAsInteger,xAsInteger,sAsLongRandomizeFori=1To30x=Int(Rnd*100)+1Printx,
for(m=100;m再问:最后一个t=0;是什么作用,新手不懂啊再答:t=0是为了能进入这一个循环,for(i=2;i
#include#includeintmian(void){intarr[50]={0};srand((unsignedint)time(NULL));intnIndex=0;for(;nIndex{
#include <iostream> // 你没有引入iostream头文件#include <iomanip>using
用什么语言呢?C还是PASCAL、VB?再问:vc++再答:#include<stdio.h>main(){ longa[30],i; a[0]=1;a[1]=1;&n